Hello there.
<span>Which VIIA element doesn't have stable isotopes in nature?
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Answer:
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Explanation:
If the item is faulty or a new member. The list of the most popular games, but the most important part . The may have a 2nd year and is 19th, but the 15th of June, so that we are able, I think it was not found. I have a look. I have been a while to find nansjsns the UK and Ireland 2 to be able the same as the first time, and a half. The comments box. chart. This will be able to make hhhj the most of the most important things in my job. The list of neighbouring, I think it would like the idea of the best of luck. This is an excellent job in a new job, but I am a bit more. We have been a while to reply, but the page, change of name of a 3, I
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I didn't know this question answer
i don't know this question answer
Explanation:

<em>According to <u>le ch</u></em><em><u>-</u></em><em><u>atelier'</u></em><em><u>s</u></em><em><u> </u></em><em><u>principle</u> when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.</em>
When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

Answer:
0,13 moles of acid are produced
Explanation:
The reaction of the problem is:
PCl₅ + 4H₂O → 5HCl + H₃PO₄
Based on the reaction, 1 mole of PCl₅ produces 6 moles of acid (5 moles of HCl + 1 mole of H₃PO₄).
The molecular mass of PCl₅ is:
1P = 30,97g/mol + 5Cl = 5×35,45g/mol = <em>208,24 g/mol</em>
That means 4,5g of PCl₅ are:
4,5g PCl₅×(1mol / 208,24g) = 0,0216 moles of PCl₅. As 1 mole of PCl₅ produces 6 moles of acid, 0,0216 moles of PCl₅ produce:
0,0216 moles PCl₅ × (6 moles acid / mole of PCl₅) =
<em>0,13 moles of acid are produced</em>
I hope it helps!
corrected question:
Determining Density and Using Density to Determine Volume or Mass
(a) Calculate the density of mercury if 1.00 × 10 g occupies a volume of 7.36 cm³
(b) Calculate the volume of 65.0 g of liquid methanol (wood alcohol) if its density is 0.791 g/mL.
(c) What is the mass in grams of a cube of gold (density = 19.32 g/cm) if the length of the cube is 2.00 cm?
(d) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm³ A student needs 15.0 g of ethanol for an experiment. If the density of ethanol is 0.789 g/mL, how many milliliters of ethanol are needed? What is the mass, in grams, of 25.0 mL of mercury (density = 13.6 g/mL)?
Answer:
density = 
ρ=m/v ,m=ρv, v=m/ρ
(a)m=1*10g , v=7.36cm³
ρ=10/7.36 =1.36g/cm³
(b) m=65g, ρ=0.791 g/mL.
v= 65/0.791 =82.17g/mL
(c) ρ=19.32g/cm³, l=2cm, v=l³=8cm³
m=19..32*8=154.56g/cm³
(d) mass of copper=374.5g , v=41.8cm³
ρ=374.5/41.8 =8.96g/cm³
mass of ethanol=15g, density of ethanol=0.789g/mL
v=15/0.789 =19.01mL
volume of mecury=25mL, density of mercury=13.6g/mL
m=25*13.6=340g