Our values can be defined like this,



The problem can be solved for part A, through the Work Theorem that says the following,

Where
KE = Kinetic energy,
Given things like that and replacing we have that the work is given by
W = Fd
and kinetic energy by

So,

Clearing F,

Replacing the values


B) The work done by the wall is zero since there was no displacement of the wall, that is d = 0.
As the rocket is launched from the ground its height will go on increasing till it stops
So the height of rocket will be maximum when its speed becomes zero
so here we can use energy conservation theory




So it will reach upto height 7.35 m
The formula for acceleration is force divided by mass.
Force = 50 N
Mass = 200 kg
Acceleration = ???


~~
Acceleration = 0.25 m/s²
~~
Next time use, f = ma in a triangle,
F
M A
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
Answer:
Explanation:
Given
acceleration a =2.2 m/s^2
Force F(t) is given by
F(t)=5.40 t N/s
Power supplied by this force at different time t is given by
Power
velocity at any instant t is given by
v=at
Power
Power
at t=1 s
Power =11.88 W
at t=2 s
Power
at =4 s
Power