This problem is asking to predict the pressure in the container at a temperature of 1,135 K with no apparent background; however, in similar problems we can be given a graph having the pressure on the y-axis and the temperature on the x-axis and a trendline such as on the attached file, which leads to a pressure of 21.2 atm by using the given equation and considering the following:
<h3>Graph analysis.</h3>
In chemistry, experiments can be studied, modelled and quantified by using graphs in which we have both a dependent and independent variable; the former on the y-axis and the latter on the x-axis.
In addition, when data is recorded and graphed, one can use different computational tools to obtain a trendline and thus, attempt to find either the dependent or independent value depending on the requirement.
In this case, since the provided trendline by the graph and the program it was put in is y = 0.017x+1.940, we understand y stands for pressure and x for temperature so that we can extrapolate this equation even beyond the plotted points, which is this case.
In such a way, we can plug in the given temperature to obtain the required pressure as shown below:
y = 0.017 ( 1,135 ) + 1.940
y = 21.2
Answer that is in atm according to the units on the y-axis:
Learn more about trendlines: brainly.com/question/13298479
Answer:
Asnwer to your question
Explanation:
Can you add a picture or anything like that?
Answer:
Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom. ... Covalent compounds tend to be soft, and have relatively low melting and boiling points.
The differences, as illustrated by the attached table, are that the particles of a colloid are smaller than those of a suspension, and that the particles do not separate out in a colloid but they do in a suspension. As an extension of the latter property, a colloid cannot be separated by filtration while a suspension can be. The optical properties are useful to make a quick determination.
Answer:
Volume of methanol present in solution = less than 3 ml
Explanation:
Given:
Volume of solution = 750 ml
Find:
Volume of methanol present in solution
Computation:
Volume of methanol present in solution = Volume of solution x 0.4%
Volume of methanol present in solution = 750 ml x 0.4%
Volume of methanol present in solution = 3 ml
Volume of methanol present in solution = less than 3 ml