Potential energy (PE ) = m g h
Where:
m = mass = 3800 kg
g = acceleration due gravity = 10 m/s^2
h = heigth = 110 meters
Replacing:
PE = 3800 * 10 * 110 = 4,180,000 J
Answer:

Explanation:
According to “Newton's second law”
“Force” is “mass” times “acceleration”, or F = m× a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass
Force = mass × acceleration

Given that,
Mass = 5.32 kg


F = 12.7N
Normal force = mg + F sinx,
“m” being the object's "mass",
“g” being the "acceleration of gravity",
“x” being the "angle of the cart"

To find normal force substitute the values in the formula,
Normal force = 5.32 × 9.8 + 12.7 × sin(-28.7)
Normal force = 52.136 + 12.7 × 0.480
Normal force = 52.136 + 6.096
Normal force = 58.232 N
<u>Acceleration of the cart</u>:




Explanation:
It is given that,
Length of the helicopter, l = 3.1 m
The helicopter rotates, the length of helicopter will become the radius of circular path, r = 3.1 m
Angular speed of the helicopter, 
(a) The centripetal acceleration in terms of angular velocity is given by :



(b) Let v is the linear speed of the tip. The relation between the linear and angular speed is given by :


v = 90.89 m/s

Hence, this is the required solution.
Periodic motion implies that the ride oscillates back and forth. The period is the time it takes to complete one cycle. Therefore it would be the swing.
Explanation:
O + 6V = 9V, so O = 3V
P = 9V as it is parallel to the 9V power supply.