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Mrrafil [7]
3 years ago
14

On a guitar, the longest string vibrates slowly, and the shortest string vibrates very quickly. What conclusion can be made abou

t the sound that each string makes? A) The long string makes a loud sound and the short string makes a soft sound, because things that are longer make louder sounds. B) The long string makes a soft sound and the short string makes a loud sound, because things that are longer make softer sounds. C) The long string makes a high-pitched sound and the short string makes a low-pitched sound, because things that vibrate slowly have a higher pitch. D) The long string makes a low-pitched sound and the short string makes a high-pitched sound, because things that vibrate slowly have a lower pitch.
Physics
1 answer:
Nadya [2.5K]3 years ago
5 0

what's up? this answer is D. best of luck with your studies

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vector is the answer of this blank

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The magnetic field at the equator points north. if you throw a positively charged object (for example, a baseball with some elec
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Recall the equation for magnetic force:

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If the magnetic field points towards N and you throw E, then the magnetic force would point up, or out of the page. Use the right-hand rule. You point your finger towards the direction of the object, and curl your finger to the magnetic field. Your thumb is the direction of the magnetic force.

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U235 + n → Xe134 + Sr100 + 2n
xenn [34]
Nuclear fission formula by the looks of it. Possibly how Professor Lisa Meitner realised that she had split the atomic nucleus. The Xenon and the Strontium (Xe and Sr) would presumably show up in a radio chemical assaying test at her university. 
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Note in the fission equation, that out come two neutrons. They go off and produce a similar fission in another U235 nucleus into a chain reaction which, i not moderated by, say, Boron, can end up as a "mushroom cloud".
8 0
3 years ago
True or False.<br>1. Electromagnetic radiation comes from nature such as deep within<br>the Earth.​
Dahasolnce [82]

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yes

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5 0
3 years ago
Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2
aleksandr82 [10.1K]

Answer:

The curl is 0 \hat x -z^2 \hat y -4xy \hat z

Explanation:

Given the vector function

\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z

We can calculate the curl using the definition

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|

Thus for the exercise we will have

\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|

So we will get

\nabla  \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z

Working with the partial derivatives we get the curl

\nabla  \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z

6 0
4 years ago
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