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2 years ago

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1. The cell in this demonstration began mitosis with two chromosomes. How many chromosomes did it have at the end of mitosis?

1 answer:

sasho [114]2 years ago

7 0

Once mitosis is complete, the cell has two groups of 46 chromosomes, each enclosed with its nuclear membrane. The cell then splits in two by a process called cytokinesis, creating two clones of the original cell, each with 46 monovalent chromosomes.
When one cell divides into two, both must have a copy of the genetic information. Therefore, before cell division occurs, the genes must also make duplicates of themselves so that all the important genetic information ends up in each of the new cells.
Centromeres.… that hold together the two chromatids (the daughter strands of a replicated chromosome). The centromere is the point of attachment of the kinetochore, a structure to which the microtubules of the mitotic spindle become anchored.

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How many molecules are in the substance formula of 2C6H1206 (use coefficients)

FrozenT [24]

<u>Answer:</u> The number of formula units present in 2 moles of $C_6H_{12}O_6$ are $1.2044\times 10^{24}$

<u>Explanation:</u>

Formula units are defined as the number of molecules or atoms present in 1 mole of a compound or element respectively.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of formula units

Here, 2 represents the number of moles of $C_6H_{12}O_6$

We are given:

Moles of $C_6H_{12}O_6$ (glucose) = 2 moles

Number of formula units of $C_6H_{12}O_6=(2\times 6.022\times 10^{23})=1.2044\times 10^{24}$

Hence, the number of formula units present in 2 moles of $C_6H_{12}O_6$ are $1.2044\times 10^{24}$

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3 years ago

What prefix should be used to name a hydrocarbon that has a six-carbon parent chain?a.hex- b.meth- c.non- d.sept-

liberstina [14]

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4 years ago

Give the electron configuration of vanadium (V), atomic number 23

saveliy_v [14]

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³ or [Ar] 4s²3d³

<h3>Further explanation</h3>

Given

Vanadium, atomic number 23

Required

The electron configuration

Solution

In an atom, there are levels of energy in the shell and subshell

This energy level is expressed in the form of electron configurations.

Charging electrons in the subshell uses the following sequence:

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc. </em>

The electron configuration is based on the atomic number which indicates the number of electrons of the atom

Vanadium has the atomic number 23, so the number of electrons = 23

Electron configuration:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³

or we can write it using the noble gas notation

[Ar] 4s²3d³

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borishaifa [10]

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