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MaRussiya [10]
2 years ago
14

Organelles float around in the cell's _________.

Chemistry
2 answers:
Rufina [12.5K]2 years ago
7 0

Answer:

Cytoplasm

Explanation:

Organelles float around in the cell’s <u>Cytoplasm </u>

Hope this helps!

Margarita [4]2 years ago
4 0
Organelles float around in the cell’s cytoplasm
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Ksivusya [100]

Answer:

it dependes on the material

Explanation:

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2 years ago
How would adding the catalyst nitrogen monoxide (NO) affect this reaction?
marin [14]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.

This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.

It does not affect the concentration of the reactants.

For the given reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is SO_3

Hence, the correct answer is Option A.

5 0
3 years ago
Read 2 more answers
Question 1
REY [17]

Answer:

An atom of neon-20 has one fewer proton and two fewer neutrons than an atom of sodium-23.

Explanation:

Neon - 20 and Sodium - 23

Neon - 20

Protons = 10

Neutrons = 10

Sodium - 23

Protons = 11

Neutrons = 12

With the information above and checking the options;

An atom of neon-20 has one fewer proton and two fewer neutrons than an atom of sodium-23.

This option is correct.

5 0
3 years ago
Express the concentration of a 0.0390 M aqueous solution of fluoride, F − , in mass percentage and in parts per million (ppm). A
Vadim26 [7]

Answer:

Mass percentage → 0.074 %

[F⁻] = 741 ppm

Explanation:

Aqueous solution of flouride → [F⁻] = 0.0390 M

It means that in 1L of solution, we have 0.0390 moles of F⁻

We need the mass of solution and the mass of 0.0390 moles of F⁻

Mass of solution can be determined by density:

1g/mL = Mass of solution / 1000 mL

Note: 1L = 1000mL

Mass of solution: 1000 g

Moles of F⁻ → 0.0390 moles . 19g /1 mol = 0.741 g

Mass percentage → (Mass of solute / Mass of solution) . 100

(0.741 g / 1000 g) . 100 = 0.074 %

Ppm = mass of solute . 10⁶ / mass of solution (mg/kg)

0.741 g . 1000 mg/1g = 741 mg

1000 g . 1 kg/1000 g = 1kg

741 mg/1kg = 741 ppm

5 0
3 years ago
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