Tin and Hydrofluoric Acid reacts as shown,
<span> Sn + 2 HF </span>→ SnF₂<span> + H</span>₂
According to Equation,
40.02 g (2 Moles) HF Required = <span>1 Mole of Sn for complete Reaction
So,
40 g of HF will require = X Moles of Sn
Solving for X,
X = (40 g </span>× 1 Mole) ÷ 40.02 g
X = 0.999 Moles ≈ 1 Mole
Result:
40 g of HF requires 1 Mole of Tin (Sn) for complete Reaction to produce SnF₂ and H₂.
Answer:
See Explanation
Explanation:
Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.
This implies that this compound Pb2O3 (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.
Hence Pb2O3 contains PbO and PbO2 units.
D: <span>Coronal Mass Ejections
e: Solar wind
f: </span><span>solar wind and magnetic field and Auroras
C1: single
C2: binary
C3: masses
C4: clusters
D1: </span><span>spectrum and color
D2: temperature
a: red
b: blue-white
3: </span><span>H-R diagram
4: main
a: </span><span>top and giants
b: </span>bottom and dwarfs