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evablogger [386]
2 years ago
5

Assign rateMPH with the corresponding rate in miles per hour given a user defined rateKPH, which is a rate in kilometers per hou

r. Use the local function KilometersToMiles. Your Solution g function distanceMiles = CalculateDistance(timeHours, rateKPH) % timeHours: Time in hours A % rateKPH: Rate in kilometers rateMPH = rateKPH; % Call KilometersToMiles function (below) to assign % rateMPH with the corresponding speed in miles per hour distanceMiles = rateMPH * timeHours; end % Do not modify the function below function milesValue = KilometersToMiles(KilometersValue) milesValue = KilometersValue * 0.6213712; 15 end Code to call your function when you click Run Calculate distance(1, 40)

Engineering
2 answers:
Marina86 [1]2 years ago
8 0

Answer:

I attached the screenshot of the code and also the output variable.

Explanation:

The code is well commented, the only things required to be done is to add just another line and implement the below function

zaharov [31]2 years ago
7 0

Answer:

Here is the code for you:

function distanceMiles = CalculateDistance(timeHours, rateKPH)

%timeHours: Time in hours

%rateKPH: Rate in kilometers

rateMPH = KilometersToMiles(rateKPH); %Call KilometersToMiles function(below) to assign

%rateMPH with the corresponding speed in miles per

%hour

distanceMiles = rateMPH * timeHours;

end

function milesValue = KilometersToMiles(KilometersValue)

milesValue = KilometersValue * 0.6213712;

end

And the output screenshot is: [Attached]

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The diffusion coefficients for species A in metal B are given at two temperatures:
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Answer:

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Explanation:

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I will be using R in the equation instead of k_b as the problem asks for molar activation energy

I will be using

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and

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So:

ln(6.69*10^{-17})=ln(D_0) -\frac{Q_d}{R*(1030+273)}

and

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You might notice that these equations have the form of  

d=y-ax

You can solve this equation system easily using calculator, and you will eventually get

D_0 =6.11*10^{-11}\ m^2/s\\ Q_d=1.49 *10^3\ J/mol

After you got those 2 parameters, the rest is easy, you can just plug them all   including the given temperature of 1180°C into the Arrhenius equation

6.11*10^{-11}e^{\frac{149\ 000}{8.143*(1180+273)}

And you should get D = 2.76*10^-16 m^/s as an answer for c)

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