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ycow [4]
2 years ago
6

Alice, Becky, and Charlie decided to compete in a 225m run. When Alice crossed the finish line, Becky was 15m behind her. When B

ecky crossed the finish line, Charlie was 15m behind her. How far was Charlie behind Alice when Alice crossed the finish line if all three run at their own constant speed? 80 points! Explanation
Mathematics
2 answers:
Viktor [21]2 years ago
4 0

Answer:

2.6/4

Step-by-step explanation:

6+ 67+674 = 747

hope it will help you

vova2212 [387]2 years ago
4 0

Answer:

Charlie was 30 m behind Alice when she crossed the finish line.

Therefore, Charlie had ran 175 m at the point when Alice crossed the finish line.

Step-by-step explanation:

If Becky was 15 m behind Alice, and Charlie was 15 m behind Becky, then Charlie was 15 + 15 = 30 m behind Alice.

Total distance Charlie had run when Alice crossed the finish line:

225 - 30 = 175 m

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There are 162 magazines and books in a library. There are 54 more books
Strike441 [17]

Answer:

108 books.

Step-by-step explanation:

Let the number of magazines = m

Let the number of books = b

<u>Given the following data;</u>

Total number of m & b = 162

<em>Translating the word problem into an algebraic equation, we have;</em>

b = m + 54 ......equation 1

m + b = 162 ......equation 2

<em>Substituting equation "1" into equation "2" we have;</em>

m + m + 54 = 162

2m + 54 = 162

2m = 162 - 54

2m = 108

m = \frac {108}{2}

m = 54

Now to find the number of books;

b = m + 54

Substituting the value of "m" into the equation, we have;

b = 54 + 54

<em>b = 108</em>

<em>Therefore, the total number of books in the library is 108 books. </em>

7 0
3 years ago
Solve this expression using the distributive property: 5 (2x + 7). *<br> plz help fast
dlinn [17]

Answer:

10x + 35

Step-by-step explanation:

5 0
3 years ago
If sec ⁡ θ = − 2 secθ=−2 and the reference angle of θ θ is 6 0 ∘ 60 ∘ , find both angles in degrees from 0 ∘ ≤ θ &lt; 36 0 ∘ 0 ∘
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What is the value of y in the equation 5x + 2y =
a_sh-v [17]

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Not Enough Details

Step-by-step explanation:

8 0
3 years ago
Yesterday morning at 8 a.m. the temperature was -14˚F. At noon it was 10 degrees warmer. The temperature increase between noon a
OLEGan [10]
The temperature was -14°F at 8 a.m.

At noon is was 10 degrees warmer - the temperature increase was 10°F
-14°F + 10°F = -4°F

The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
10°F x 2 = 20°F

We want to know the temperature at 4 p.m. so we just add it up to the previous result.
-4°F + 20°F = 16°F

16°F is the correct answer
4 0
3 years ago
Read 2 more answers
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