Answer:
![a=368.97\ m/s^2](https://tex.z-dn.net/?f=a%3D368.97%5C%20m%2Fs%5E2)
Explanation:
Given that,
Initial angular velocity, ![\omega=0](https://tex.z-dn.net/?f=%5Comega%3D0)
Acceleration of the wheel, ![\alpha =7\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D7%5C%20rad%2Fs%5E2)
Rotation, ![\theta=14\ rotation=14\times 2\pi =87.96\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D14%5C%20rotation%3D14%5Ctimes%202%5Cpi%20%3D87.96%5C%20rad)
Let t is the time. Using second equation of kinematics can be calculated using time.
![\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s](https://tex.z-dn.net/?f=%5Ctheta%3D%5Comega_it%2B%5Cdfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2%5C%5C%5C%5Ct%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctheta%7D%7B%5Calpha%20%7D%7D%20%5C%5C%5C%5Ct%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%2087.96%7D%7B7%7D%7D%20%5C%5C%5C%5Ct%3D5.01%5C%20s)
Let
is the final angular velocity and a is the radial component of acceleration.
![\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s](https://tex.z-dn.net/?f=%5Comega_f%3D%5Comega_i%2B%5Calpha%20t%5C%5C%5C%5C%5Comega_f%3D0%2B7%5Ctimes%205.01%5C%5C%5C%5C%5Comega_f%3D35.07%5C%20rad%2Fs)
Radial component of acceleration,
![a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Comega_f%5E2r%5C%5C%5C%5Ca%3D%2835.07%29%5E2%5Ctimes%200.3%5C%5C%5C%5Ca%3D368.97%5C%20m%2Fs%5E2)
So, the required acceleration on the edge of the wheel is
.
Answer:
well, it is not a solid path and thats a teeny tiny fact
Answer:
![\fbox {D. Isobaric}](https://tex.z-dn.net/?f=%5Cfbox%20%7BD.%20Isobaric%7D)
Explanation:
The process during which pressure remains constant is called an isobaric process.
Answer:
Surface tension in water
Friction between tires and pavement
Dissolution of salt in water
Explanation:
Surface tension in water: It is due to the electrostatic force of attraction (cohesive force) between water molecules.
Friction between tires and pavement: It is due to the attractive force between tires and pavement.
Dissolution of salt in water: The ions of
and
separate due to the strong attraction of water molecules.