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natta225 [31]
3 years ago
14

What is the change in enthalpy in joules when 5.44 x 10- mol of AgCl dissolves in water according to the following chemical equa

tion:
AgCl(s) rightarrow Ag+(aq)+ Cl-(aq) AH=65.5 kj
Chemistry
1 answer:
ra1l [238]3 years ago
4 0

Answer:

\Delta H=35.3J

Explanation:

Hello,

In this case, since the dissolution of silver chloride involves a change in enthalpy of 65.5kJ per 1 mole  when undergone, for 5.44x10⁻⁴ moles, the enthalpy change is:

\Delta H=65.5\frac{kJ}{1mol}*5.44x10^{-4}mol\\ \\\Delta H=0.0353kJ*\frac{1000J}{1kJ}\\ \\\Delta H=35.3J

Best regards.

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