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FinnZ [79.3K]
2 years ago
15

What is the osmotic pressure of a solution of FeCl3(aq) in which 69.5 g of FeCl3(s) (molar mass = 162.20 g mol-1) are dissolved

in a solution with a total volume of 2.35 L at 35.0 °C?
Chemistry
1 answer:
ivolga24 [154]2 years ago
5 0

The osmotic pressure of the solution is 25.48atm

Data;

  • Mass = 69.5g
  • Molar mass = 162.20g/mol
  • Volume = 2.35L
  • Temperature = 35.0^oC
<h3>Osmotic Pressure</h3>

The osmotic pressure of the solution is calculated as

\pi = iMRT

  • i = Vant Hoff Factor
  • M = molarity
  • R = gas constant
  • T = Temperature

The Vant hoff factor of the factor = 4

Let's calculate the molarity of the solution;

M = \frac{number of moles}{volume}

Number of moles = mass / molar mass

n = \frac{mass}{molar mass} \\

substitute the values into the formula and solve for it

n = \frac{69.5}{162.20} \\n = 0.428 moles

The molarity of the solution is calculated as

M = \frac{number of moles}{volume} \\M = \frac{0.428}{2.35} = 0.182 mol/L

The osmotic pressure of the solution is calculated as

\pi = iMRT\\\pi = 4 * 0.182 * 35\\\pi = 25.48 atm

The osmotic pressure of the solution is 25.48atm

Learn more on osmotic pressure here;

brainly.com/question/8195553

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