Answer:
1.429 g of N₂
Explanation:
The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:
- N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆ 2NH₃ ₍g₎
One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.
We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.
no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol
and the actual yield is 98% , then the theoretical number of moles that would be produced are:
- percent yield = (actual yield / theoretical yield) × 100
98 = (0.1 mol / theoretical yield) × 100
theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol
using cross multiplication
1 mol of N₂ → 2 mol of NH₃.
?? mol of N₂ → 0.102 mol of NH₃.
no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol
Last step is to convert the moles back to grams using:
mass = (no of moles of N₂ * molar mass of N₂)
= (0.051 mol * 28 g/mol) = 1.429 g
The perimeter of a square is P=4a because a P stands for perimeter and it’s 4 because a square has 4 sides
<u>Answer</u>: Conduction, convection, and radiation move energy from the Sun to Earth and throughout Earth.
Without more information about the experiment itself, I would choose the above answer as correct. All the other statements are correct, however none of them relates to the earth distribution processes on Earth. The last statement does.
Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.
Explanation :
First we have to calculate the moles of phosphorus.
Now we have to calculate the moles of 
The balanced chemical reaction is:
From the balanced chemical reaction, we conclude that
As, 2 moles of phosphorous react with 3 moles of
So, 0.5 moles of phosphorous react with 
moles of
Now we have to calculate the mass of
Molar mass of = 71 g/mol
Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.
Answer:
0.24M
Explanation:
The equation for the reaction is given below:
H2SO4 + 2KOH → K2SO4 + 2H2O
From the equation above, we obtained the following information:
nA (mole of acid) = 1
nB (mole of base) = 2
Data obtained from the question include:
Va (volume of the acid) = 12mL
Ca (concentration of the acid) =?
Vb (volume of the base) = 36mL
Cb (concentration of the base) = 0.16 M
The Ca (concentration of the acid) can be obtained as follow:
CaVa/CbVb = nA/nB
Ca x 12 / 0.16 x 36 = 1 /2
Cross multiply to express in linear form as shown below:
Ca x 12 x 2 = 0.16 x 36
Divide both side by 12 x 2
Ca = 0.16 x 36/ 12 x 2
Ca = 0.24M
Therefore, the concentration of the acid is 0.24M
