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Gekata [30.6K]
3 years ago
15

2C4H10 + 13O2 -> CO2 + 10H20

Chemistry
2 answers:
GarryVolchara [31]3 years ago
5 0

Answer:

D) 1.6 mol

Explantion:

hjlf3 years ago
3 0

Answer: D) 1.6 mol

Explanation:

This is a stoichiometry problem that uses the ratios of the coefficients of the chemical equation. We see from the equation that 2 moles of C4H10 produces 10 moles of H20.  

Now if we had 8 moles of H20 then we must have started with 1.6 moles of C4H10. This is because

\frac{2 \, \, \text{moles C4H10}}{10 \, \, \text{moles H2O}} =  \frac{x \, \, \text{moles C4H10}}{8 \, \, \text{moles H2O}}\\

This gives us x = 1.6 moles of C4H10

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A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure.
daser333 [38]

Answer:

1.429 g of  N₂

Explanation:

The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:

  • N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆  2NH₃ ₍g₎  

One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.

We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.

no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol

and the actual yield is 98% , then the theoretical number of moles that would be produced are:  

  • percent yield = (actual yield / theoretical yield) × 100

98 = (0.1 mol /  theoretical yield) × 100

theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol

using cross multiplication

1 mol of N₂ → 2 mol of NH₃.

?? mol of N₂ → 0.102 mol of NH₃.

no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol

Last step is to convert the moles back to grams using:

mass = (no of moles of N₂  * molar mass of N₂)

         = (0.051 mol * 28 g/mol) = 1.429 g

5 0
4 years ago
The perimeter of a square ​
diamong [38]
The perimeter of a square is P=4a because a P stands for perimeter and it’s 4 because a square has 4 sides
4 0
3 years ago
ANSWER FOR: How did the lab activities help you answer the lesson question "How do the processes of conduction, convection, and
Alenkinab [10]

<u>Answer</u>: Conduction, convection, and radiation move energy from the Sun to Earth and throughout Earth.

Without more information about the experiment itself, I would choose the above answer as correct. All the other statements are correct, however none of them relates to the earth distribution processes on Earth. The last statement does.

8 0
3 years ago
Read 2 more answers
Carlos is making phosphorus trichloride using the equation below. He uses 15.5 g of phosphorus and collects 50.9 g of phosphorus
Oxana [17]

Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.

Explanation :

First we have to calculate the moles of phosphorus.

\text{Moles of phosphorus}=\frac{\text{Mass of phosphorus}}{\text{Molar mass of phosphorus}}

\text{Moles of phosphorus}=\frac{15.5g}{31g/mol}=0.5mol

Now we have to calculate the moles of Cl_2

The balanced chemical reaction is:

2P+3Cl_2\rightarrow 2PCl_3

From the balanced chemical reaction, we conclude that

As, 2 moles of phosphorous react with 3 moles of Cl_2

So, 0.5 moles of phosphorous react with \frac{3}{2}\times 0.5=0.75 moles of Cl_2

Now we have to calculate the mass of Cl_2

\text{Mass of }Cl_2=\text{Moles of }Cl_2\times \text{Molar mass of }Cl_2

Molar mass of Cl_2 = 71 g/mol

\text{Mass of }Cl_2=0.75mol\times 71g/mol=53.25g

Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.

4 0
4 years ago
Read 2 more answers
Information related to a titration experiment is given in the balanced equation and table below.
Scorpion4ik [409]

Answer:

0.24M

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation above, we obtained the following information:

nA (mole of acid) = 1

nB (mole of base) = 2

Data obtained from the question include:

Va (volume of the acid) = 12mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 36mL

Cb (concentration of the base) = 0.16 M

The Ca (concentration of the acid) can be obtained as follow:

CaVa/CbVb = nA/nB

Ca x 12 / 0.16 x 36 = 1 /2

Cross multiply to express in linear form as shown below:

Ca x 12 x 2 = 0.16 x 36

Divide both side by 12 x 2

Ca = 0.16 x 36/ 12 x 2

Ca = 0.24M

Therefore, the concentration of the acid is 0.24M

6 0
4 years ago
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