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2 years ago

Classify Angle 3 & Angle 4 by choosing the correct term from the choices below.

Mathematics

2 answers:

vlabodo [156]2 years ago

8 0

Classify Angle 3 & Angle 4 by choosing the correct term from the choices below

adjacent

adjacentcomplementary

adjacentcomplementaryvertical

adjacentcomplementaryverticalstraight

$\large\underline{\underline{\maltese{\orange{\pmb{\sf{\: Explanation :-}}}}}}$

The given angles are Adjacent
Adjacent angles:- The angles that share a common side and have a common vertex are called Adjacent Angles...~

nika2105 [10]2 years ago

6 0

$\qquad \qquad\huge \bf༆ Answer ༄$

The given angles 3 and 4 shares a common arm, therefore the angles are known as Adjacant Angles

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Prove each of the following statements below using one of the proof techniques and state the proof strategy you use.

pochemuha

Answer:

See below

Step-by-step explanation:

a) Direct proof: Let m be an odd integer and n be an even integer. Then, there exist integers k,j such that m=2k+1 and n=2j. Then mn=(2k+1)(2j)=2r, where r=j(2k+1) is an integer. Thus, mn is even.

b) Proof by counterpositive: Suppose that m is not even and n is not even. Then m is odd and n is odd, that is, m=2k+1 and n=2j+1 for some integers k,j. Thus, mn=4kj+2k+2j+1=2(kj+k+j)+1=2r+1, where r=kj+k+j is an integer. Hence mn is odd, i.e, mn is not even. We have proven the counterpositive.

c) Proof by contradiction: suppose that rp is NOT irrational, then rp=m/n for some integers m,n, n≠. Since r is a non zero rational number, r=a/b for some non-zero integers a,b. Then p=rp/r=rp(b/a)=(m/n)(b/a)=mb/na. Now n,a are non zero integers, thus na is a non zero integer. Additionally, mb is an integer. Therefore p is rational which is contradicts that p is irrational. Hence np is irrational.

d) Proof by cases: We can verify this directly with all the possible orderings for a,b,c. There are six cases:

a≥b≥c, a≥c≥b, b≥a≥c, b≥c≥a, c≥b≥a, c≥a≥b

Writing the details for each one is a bit long. I will give you an example for one case: suppose that c≥b≥a then max(a, max(b,c))=max(a,c)=c. On the other hand, max(max(a, b),c)=max(b,c)=c, hence the statement is true in this case.

e) Direct proof: write a=m/n and b=p/q, with m,q integers and n,q nonnegative integers. Then ab=mp/nq. mp is an integer, and nq is a non negative integer. Hence ab is rational.

f) Direct proof. By part c), √2/n is irrational for all natural numbers n. Furthermore, a is rational, then a+√2/n is irrational. Take n large enough in such a way that b-a>√2/n (b-a>0 so it is possible). Then a+√2/n is between a and b.

g) Direct proof: write m+n=2k and n+p=2j for some integers k,j. Add these equations to get m+2n+p=2k+2j. Then m+p=2k+2j-2n=2(k+j-n)=2s for some integer s=k+j-n. Thus m+p is even.

7 0

3 years ago

ABCD diagonals intersect at E. If m∠BAC=4x+5 and m∠CAD=5x-14, then find m∠CAD.

Travka [436]

Answer: m∠CAD = 81°

Step-by-step explanation: Diagonal is a line that unites opposite sides.

ABCD is a prallelogram. One property of diagonal in a parallelogram is it separates the parallelogram in 2 congruent triangles.

The figure below shows ABCD with its diagonals.

Since diagonal divides a parallelogram in 2 congruent triangles, it means the internal angles are also congruent. So

m∠BAC = m∠CAD

4x + 5 = 5x - 14

x = 19

Then, m∠CAD is

m∠CAD = 5(19) - 14

m∠CAD = 81

The angle m∠CAD is 81°.

7 0

3 years ago

How is 16.666666 . . . written as a fraction

AVprozaik [17]

1/3 ANS

hope this helps and i hope u ace it

5 0

2 years ago

A set of golf clubs that costs 7,000 dirhems are on sale for 20% off the regular price. What is the sale price of the

hammer [34]

Answer:

The answer is $1400.

Step-by-step explanation:

The main question here is, what is the sale price of the golf clubs?

1. Let's compute for 20% of 7,000.

20%×7000
20/100×7000
20×70
1400

<h2>You should get 1400.</h2>

Hope this helps and if you could mark this as brainliest. Thanks!

7 0

3 years ago

PLEASE help me I need help

Alexxandr [17]

Answer:

Step-by-step explanation:

The rest you can elimate because of obvious inferring and reasoning so process of elimination

7 0

3 years ago

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