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In-s [12.5K]
2 years ago
13

Classify Angle 3 & Angle 4 by choosing the correct term from the choices below.

Mathematics
2 answers:
vlabodo [156]2 years ago
8 0

Classify Angle 3 & Angle 4 by choosing the correct term from the choices below

adjacent

adjacentcomplementary

adjacentcomplementaryvertical

adjacentcomplementaryverticalstraight

\large\underline{\underline{\maltese{\orange{\pmb{\sf{\: Explanation :-}}}}}}

  • The given angles are Adjacent
  • <u>Adjacent</u><u> </u><u>angles</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>angles</em><em> </em><em>that</em><em> </em><em>share</em><em> </em><em>a</em><em> </em><em>common</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>common</em><em> </em><em>vertex</em><em> </em><em>are</em><em> </em><em>called</em><em> </em><em>Adjacent</em><em> </em><em>Angles</em><em>.</em><em>.</em><em>.</em><em>~</em>
nika2105 [10]2 years ago
6 0

\qquad \qquad\huge \bf༆ Answer ༄

The given angles 3 and 4 shares a common arm, therefore the angles are known as Adjacant Angles

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A caterpillar crawling in a straight line across a coordinate plane starts at point (-3,
Irina18 [472]

9514 1404 393

Answer:

  15

Step-by-step explanation:

In vector form, the equation of point p on the line can be written as ...

  p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t

  p = (-3, -4) +t(28, 42)

  p = (-3, -4) +14t(2, 3)

where t takes on any value between 0 and 1.

If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.

There are 15 values that n can have in the allowed range.

The caterpillar touches 15 points with integer coordinates.

7 0
3 years ago
I need help this is 7th grade homework
Alla [95]
Number of weeks in a year divided by 6, then multiply that answer by $108
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3 years ago
Write the equation of the line that is parallel to y=-0.75x and that passes through the point (8,0)
Mila [183]

Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6

Step-by-step explanation:

Given equation of line is:

y=-0.75x

The coefficient of x is the slope of the line so the slope of given line is: -0.75

As parallel lines have equal slopes so the required equation of line will have the same slope.

The slope-intercept form is:

y = mx+b

Putting the value of the slope

y = -0.75x+b

To find the value of b, putting the point in the equation

0 = -0.75(8)+b\\0 = -6+b\\b = 6

Putting the values of m and b, we get

y = -0.75x-6

Hence,

Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6

Keywords: Equation of line, Slope-intercept form

Learn more about equation of line at:

  • brainly.com/question/10435816
  • brainly.com/question/10435836

#LearnwithBrainly

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Write an expression showing 5 less than the number .
loris [4]

Answer:

if the number is anything then I pick 10 so 5 because 10 - 5 = 5 I guess lol

Step-by-step explanation:

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3 years ago
Read 2 more answers
Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −
crimeas [40]

Solving quadratic equations, it is found that he needs to charge:

1. He needs to charge $40 to break even.

2. He needs to charge $30 for a profit of $600.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

The profit equation in this problem is:

P(x) = -3x² + 150x - 1200.

He breaks even when P(x) = 0, hence:

-3x² + 150x - 1200 = 0.

The coefficients are a = -3, b = 150, c = -1200, hence:

  • \Delta = 150^2 - 4(-3)(-1200) = 8100
  • x_1 = \frac{-150 + \sqrt{8100}}{-6}
  • x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40

He needs to charge $40 to break even.

For a profit of $600, we have that P(x) = 600, hence:

-3x² + 150x - 1200 = 600.

-3x² + 150x - 1800 = 0.

The coefficients are a = -3, b = 150, c = -1800, hence:

  • \Delta = 150^2 - 4(-3)(-1800) = 900
  • x_1 = \frac{-150 + \sqrt{900}}{-6}
  • x_2 = \frac{-150 - \sqrt{900}}{-6} = 30

He needs to charge $30 for a profit of $600.

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
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