b) Deduce the formula of potassium oxide and calcium oxide Potassium oxide .....................................................
2 answers:
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<h3>Answer:</h3>
62.3 mol Ca
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
3.75 × 10²⁵ atoms Ca
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
62.2717 mol Ca ≈ 62.3 mol Ca
<u>Answer:</u> The concentration of in the solution is
<u>Explanation:</u>
The given cell is:
Half reactions for the given cell follows:
<u>Oxidation half reaction:</u> ( × 3)
<u>Reduction half reaction:</u> ( × 2)
<u>Net reaction:</u>
Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate the concentration of ion for given EMF of the cell, we use the Nernst equation, which is:
where,
= electrode potential of the cell = 1.23 V
= standard electrode potential of the cell = +1.50 V
n = number of electrons exchanged = 6
Putting values in above equation, we get:
Hence, the concentration of in the solution is