When two electrons occupy the bonding molecular orbital above what type of bond results explain?
1 answer:
I think you forgot to include the picture so that we could easily identify the bond. No matter, I can introduce the types of bonds involved in chemistry. There are only two: the sigma bond (first picture) and the pi bond (second picture).
The sigma bond is formed when the two electrons sharing an orbital are overlapped head-on. In other words, they overlap each other entirely. While a pi bond is a side-to-side overlapping kind of sharing. That is why sigma bonds are much stronger than pi bonds.
In this case, just please refer to the picture for you to identify which type of bond is it indicated in your homework.
The sigma bond is formed when the two electrons sharing an orbital are overlapped head-on. In other words, they overlap each other entirely. While a pi bond is a side-to-side overlapping kind of sharing. That is why sigma bonds are much stronger than pi bonds.
In this case, just please refer to the picture for you to identify which type of bond is it indicated in your homework.
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Answer:
0.00369 moles of HCl react with carbonate.
Explanation:
Number of moles of HCl present initially = moles = 0.00600 moles
Neutralization reaction (back titration):
According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.
So, excess number of moles of HCl present = number of NaOH added for back titration = moles = 0.00231 moles
So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles
Hence, 0.00369 moles of HCl react with carbonate.