Answer:
Ff = 159 [N]
Explanation:
Since in the problem give us two values of friction coefficient one static and the other dynamic, it is important to keep in mind that in order to solve this problem we must know the conditions in which the sled is located. We can read that the sled is in motion, in this way we use the dynamic coefficient of friction.
The friction force is calculated as the product of normal force, by the appropriate coefficient of friction value.
Ff = N * μ
Ff = 636 * 0.25
Ff = 159 [N]
When a person is making cardiovascular gains through aerobic activity they are increasing the amount of oxygen to the heart and lungs. This keeps the heart and lungs of a person very healthy. It decreases the chance of heart diseases.
Answer:

Explanation:
If the collision is elastic and exactly head-on, then we can use the law of momentum conservation for the motion of the 2 balls
Before the collision

After the collision

So using the law of momentum conservation


We can solve for the speed of ball 1 post collision in terms of others:

Their kinetic energy is also conserved before and after collision


From here we can plug in 





