How much force is needed to stretch a spring 1.2m if the spring constant is 8.5 N/m?
1 answer:
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It can be noted that the directions west and north are perpendicular to each other. hence we can use the right angle formula for calculating total distance in these directions. Also South is just negative north. This technique is called euclidean distance norm. It is the basis of Cartesian coordinate system.
Total distance = 3.22 N + 4.75 W +1.90 S
= 1.32 N + 4.75 W
D =
D = 4.93 Km
direction = atan(N/W) = 15.53 deg north of west
Answer:
R = 4.24 x 10⁻⁴ m
Explanation:
given,
mass of the person = 60.3-kg
mass of the bullet = 10 gram = 0.01 Kg
velocity of bullet = 389 m/s
angle made with the horizontal = 45°
using conservation of momentum.
M v + m u = ( M + m ) V
60.3 x 0 + 0.01 x 389 = (60.3 + 0.01) V
V = 0.0645 m/s
for calculation of range
R = 4.24 x 10⁻⁴ m
the distance actor fall is R = 4.24 x 10⁻⁴ m
Answer:
The car traveled the distance before stopping is 90 m.
Explanation:
Given that,
Mass of automobile = 2000 kg
speed = 30 m/s
Braking force = 10000 N
For, The acceleration is
Using newton's formula
Where, f = force
m= mass
a = acceleration
Put the value of F and m into the formula
Negative sing shows the braking force.
It shows the direction of force is opposite of the motion.
For the distance,
Using third equation of motion
Where, v= final velocity
u = initial velocity
a = acceleration
s = stopping distance of car
Put the value in the equation
Hence, The car traveled the distance before stopping is 90 m.