Yo sup??
CaCO3 + 2 HCl ---------> CaCl2 + H2O + CO2
This is the balanced chemical equation
Hope this helps
Answer:
0,2,8,3
Explanation:
k shell takes 2,L shell takes 8 and M shell takes the remaining which is 3
Answer:
1.AD
2.BC
Explanation:
For aluminum phosphate AlPO4 (s) <------> Al^3+(aq) + PO4^3-(aq)
Ksp= [Al^3+] [PO4^3-]
For magnesium hydroxide
Mg(OH)2(s) <--------> Mg^2+(aq) +. 2OH^-(aq)
Ksp= [Mg2+] [2OH^-]^2
For
Answer:
25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃
Explanation:
Based on the reaction of the problem, 1 mole of Fe₂S₃ is produced from 2 moles of FeCl₃.
0.345g of Fe₂S₃ are (Molar mass: 207.9g/mol):
0.345g of Fe₂S₃ ₓ (1 mol / 207.9g) = <em>1.6595x10⁻³ moles Fe₂S₃</em>
Moles of Fe needed to produce these moles of Fe₂S₃ are:
1.6595x10⁻³ moles Fe₂S₃ ₓ ( 2 moles FeCl₃ / 1 mole Fe₂S₃) =
<em>3.3189x10⁻³ moles of FeCl₃</em>
As the percent yield of the reaction is 65.0%, the moles of FeCl₃ you need to add are:
3.3189x10⁻³ moles of FeCl₃ ₓ (100.0% / 65.0%) = <em>5.106x10⁻³ moles of FeCl₃</em>
A solution 0.200M contains 0.200 moles per L. Volume to obtain 5.106x10⁻³ moles is:
<em>5.106x10⁻³ moles of FeCl₃ ₓ ( 1L / 0.200mol) = 0.02553L = </em>
<h3>25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃</h3>
Change one of the variables and try again