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Lerok [7]
2 years ago
9

Consider the two setups below. in setup 1, conducting bodies A and B have the same temperature, while in setup 2, conducting bod

ies C and D have different temperatures-C is hotter than D.All the bodies are made of the same material.
a. will heat transfer occur in both setups?why?

b. in the setup(s) where heat transfer can occur, draw an arrow in the diagram(s) to represent the direction of heat flow between the two bodies.

c. will heat perpetually flow between the two bodies in each setup?why? ​
Chemistry
1 answer:
Kipish [7]2 years ago
8 0

The heat transfer will only occur in setup 2 and heat will only flow from C to D.

<h3>Heat energy</h3>

In a mixture between two substances of different temperatures, there is heat transfer, in which the one with a lower temperature receives this heat and the one with a higher temperature loses the heat.

In a system, the value of heat lost and received is <u>equal</u>.

So, heat will only flow in setup 2 since it is the only one that has two bodies with different temperatures, and it will flow from C to D because C has a higher temperature.

The representation of heat transfer can be done as follows:

                                                     C ⇒ D

Learn more about heat energy in: brainly.com/question/1495272

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The element Y has 13 electrons. What is the electronic configuration of
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For each of the salts on the left, match the salts on the right that can be compared directly, using Ksp values, to estimate sol
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1.AD

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How many milliliters of 0.200 M FeCl3 are needed to react with an excess of Na2S to produce 0.345 g of Fe2S3 if the percent yiel
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Answer:

25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃

Explanation:

Based on the reaction of the problem, 1 mole of Fe₂S₃ is produced from 2 moles of FeCl₃.

0.345g of Fe₂S₃ are (Molar mass: 207.9g/mol):

0.345g of Fe₂S₃ ₓ (1 mol / 207.9g) = <em>1.6595x10⁻³ moles Fe₂S₃</em>

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1.6595x10⁻³ moles Fe₂S₃ ₓ ( 2 moles FeCl₃ / 1 mole Fe₂S₃) =

<em>3.3189x10⁻³ moles of FeCl₃</em>

As the percent yield of the reaction is 65.0%, the moles of FeCl₃ you need to add are:

3.3189x10⁻³ moles of FeCl₃ ₓ (100.0% / 65.0%) = <em>5.106x10⁻³ moles of FeCl₃</em>

A solution 0.200M contains 0.200 moles per L. Volume to obtain 5.106x10⁻³ moles is:

<em>5.106x10⁻³ moles of FeCl₃ ₓ ( 1L / 0.200mol) = 0.02553L = </em>

<h3>25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃</h3>

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