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4 years ago

When one thermal equilibrium achieved between two objects ?

2 answers:

6 0

Hello! Thermal equilibrium is reached between two objects when both have the same final heat value or temperature. Meaning when ice is dropped into water, and the ice melts, the ice and water mixture will get to thermal equilbrum when the temp of the water has stabilized and the ice added has completely melted and warmed up to the water temp so ice and water are now in thermal equilibrium.
Hope this helps you understand the concept. Any questions please just ask. Thank you!!

Setler [38]4 years ago

4 0

Based on the Zeroth Law of Thermodynamics, two systems are at equilibrium when there is no heat flow, q, between the systems.

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an empty relative density bottle weights 20g. the bottle weights 40g when filled with petrol and 60g when filled with water. det

Kobotan [32]

Answer:

500 Kg/m³

Explanation:

From the question given above, the following data were obtained:

Mass of empty bottle = 20 g

Mass of bottle + petrol = 40 g

Mass of bottle + water = 60 g

Density of water = 1000 Kg/m³

Density of petrol =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty bottle = 20 g

Mass of bottle + water = 60 g

Mass of water =?

Mass of water = (Mass of bottle + water) – (Mass of empty bottle)

Mass of water = 60 – 20

Mass of water = 40 g

Converting 40 g to Kg, we have:

1000 g = 1 Kg

Therefore,

40 g = 40 × 1 Kg / 1000 g

40 g = 0.04 Kg

Next, we shall determine the volume of the bottle by calculating the volume of water. This can be obtained as follow:

Mass of water = 0.04 Kg

Density of water = 1000 Kg/m³

Volume of water =?

Density = mass / volume

1000 = 0.04 / volume

Cross multiply

1000 × volume = 0.04

Divide both side by 1000

Volume of water = 0.04 / 1000

Volume of water = 4×10¯⁵ m³

Thus, the volume of the bottle is 4×10¯⁵ m³

Next, we shall determine the mass of the petrol. This can be obtained as follow:

Mass of empty bottle = 20 g

Mass of bottle + petrol = 40 g

Mass of petrol =?

Mass of petrol = (Mass of bottle + petrol ) – (Mass of empty bottle)

Mass of petrol = 40 – 20

Mass of petrol = 20 g

Converting 20 g to Kg, we have:

1000 g = 1 Kg

Therefore,

20 g = 20 × 1 Kg / 1000 g

20 g = 0.02 Kg

Finally, we shall determine the density of the petrol. This can be obtained as follow:

Mass of petrol = 0.02 Kg

Volume of petrol = 4×10¯⁵ m³

Density of petrol =?

Density = mass / volume

Density of petrol = 0.02 / 4×10¯⁵

Density of petrol = 500 Kg/m³

4 0

3 years ago

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

EleoNora [17]

Answer : The current passing between the electrodes is, $1.056\times 10^{-2}A$

Explanation :

First we have to calculate the charge of sodium ion.

$q=ne$

where,

q = charge of sodium ion

n = number of sodium ion = $2.68\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C$

Now we have to calculate the charge of chlorine ion.

$q'=ne$

where,

q' = charge of chlorine ion

n = number of chlorine ion = $3.92\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C$

Now we have to calculate the current passing between the electrodes.

$I=\frac{q}{t}+\frac{q'}{t}$

$I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}$

$I=1.056\times 10^{-2}A$

Thus, the current passing between the electrodes is, $1.056\times 10^{-2}A$

4 0

3 years ago

In the chart, the organism Rr represents a genetically _____________ individual.

GalinKa [24]

Organism. ' s rate of mutation is directly proportional to its adaptability. .... D. The cell membrane contains genetic information of the cell. .... What cellular structure was the dialysis tubing most likelyrepresenting in this experiment? ...... C Rr and rr only ... A healthy individual is a carrier of a lethal allele but is unaffected by it.

4 0

3 years ago

Read 2 more answers

What is the oxidation number of iodine in kio4?

cestrela7 [59]

What is the oxidation number of iodine in kio4? -7?

3 0

3 years ago

Can some one help with this question too??

ira [324]

Your answer is right tho

7 0

3 years ago