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zmey [24]
2 years ago
14

(10 POINTS) I need help on a physics question please short on time

Physics
1 answer:
Novosadov [1.4K]2 years ago
5 0

Answer:

b

Explanation:

because it has the biggest number

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Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minu
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About 285 meters per minute
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4 years ago
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A shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 n frictional force. he pushes in a dire
alexandr1967 [171]

Work is calculated as the product of Force, Distance, and angular motion. In this case, the work done by gravity is perpendicular to the motion of the cart, so θ = 90°

 and W=Fdcosθ

W=35.0 N x 20.0 m x cos90

W=0 J

This means that work done perpendicular to the direction of the motion is always zero.

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3 years ago
Which of the following accurately describes the differences between the SI and English systems of measurement?
Digiron [165]
The best answer is D. The SI system, which is based on the metric system, has been more widely adopted than the English system, which is harder to use. In order to standardize measurements, the International System of Units or the SI units are commonly used around the world since they are more easy to understand and compare than the English unit.
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3 years ago
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A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywher
Scilla [17]

Answer:

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

Explanation:

The Coulomb's Law gives the force by the charges:

\vec{F} = K\frac{q_1q_2}{r^2}\^r

Let us denote the positon of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

F_1 = K\frac{Qq}{x^2 + y^2}\\F_1_x = F_1\cos(\theta)

where Θ is the angle between F_1 and x-axis.

F_1_x = K\frac{Qq}{x^2 + y^2}(\frac{x}{\sqrt{x^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

whereas

F_2_x = K\frac{-Qq}{a^2 + y^2}(-\frac{a}{\sqrt{a^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}

Finally, the x-component of the net force is

\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x

8 0
4 years ago
A car breaks down 3.5 meters away from the side of the road. 2.060 Newtons of
kogti [31]

Answer:

<h2>7.21 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 2.060 × 3.5

We have the final answer as

<h3>7.21 J</h3>

Hope this helps you

7 0
3 years ago
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