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Helga [31]
2 years ago
11

30 POINTS PLEASE HELP ME I NEED YALL PLEASE

Chemistry
2 answers:
tino4ka555 [31]2 years ago
6 0

Answer:59/150

Explanation:

Kay [80]2 years ago
4 0

6CO2 + 6H2O → C6H12O6 + 6O2

glucose produced = 1/6 x 23.6 = 3.93 moles

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You wish to measure the iron content of the well water on the new property you are about to buy. You prepare a reference standar
djverab [1.8K]

1.04 ⨯ 10^{-4} M

<h3>Explanation</h3>

<em>A</em> = <em>ε</em> \cdot l \cdot c by the Beer-Lambert law, where

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<em>A</em> and <em>ε </em>are the same for both solutions. Therefore, l \cdot c is constant; l is inversely proportional to c. The 100 mL sample would have a concentration 1/4.78 times that of the 45.0 mL reference.

The 13.0 mL standard solution has a concentration of 5.17 ⨯ 10^{-4} M. Diluting it to 45.0 mL results in a concentration of 5.17 \times 10^{-4} \times \frac{13.0}{45.0} = 1.494 M.

c is inversely related to l for the two solutions. As a result, c₂ = c_1 \cdot \frac{l_1}{l_2} = 1.494 \times 10^{-4} \times \frac{1}{4.78} = 3.126 M.

The 30.0 mL sample has to be diluted by 30.0 / 100.0 times to produce the 100.0 mL solution being tested. The 100.0 mL solution has a concentration of 3.126 M. Therefore, the 30.0 mL solution has a concentration of 3.126 \times \frac{100.0}{30.0} = 1.04 ⨯ 10^{-4} M.

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3 years ago
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Producers (autotroph)

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8 0
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while doing an experiment you got stuck and didn't know how to proceed what will you do to continue with the experiment​
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Look for extra things to do, small details, until you find a big enough one to go off that to continue

Explanation:

n/a

7 0
3 years ago
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