3 years ago

Why does benzene form a ring?

1 answer:

4 0

Answer:

<em>All of the carbon-carbon bonds have exactly the same lengths - somewhere between single and double bonds. There are delocalized electrons above and below the plane of the ring. The presence of the delocalized electrons</em>

Explanation:

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Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO

vlada-n [284]

Answer:

$2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}$

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

$2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}$

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