Answer:
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Answer:</h3>
4 m/s²
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Explanation:</h3>
From the question, we are given;
- Mass of the ball is 2.0 kg
- Acceleration of the ball is 4.2 m/s²
With the above information, we can calculate the force applied to the ball.
- From the second newton's law of motion, F = ma
- Therefore;
Net force, F = 2.0 kg × 4.2 m/s²
= 8.4 N
- We are required to determine the acceleration when the same force is applied to a steel ball with a mass of 2.1 kg.
Mass = 2.1 kg
Force = 8.4 N
But;
Force = mass × acceleration
Acceleration = Force ÷ Mass
= 8.4 N ÷ 2.1 kg
= 4 m/s²
Thus, the acceleration will be 4 m/s²
Answer: 65mph, 75mph
Explanation:
Let us assume x to be the speed of the slower train, in mph (miles per hour).
Then the speed of the other train is (x+10) mph, according to the question.
We then would have an equation like this
1.6x + 1.6(x+10) = 224.
This is because, the first addend in the left side is the distance covered by the slower train.
The second addend in the left side is the distance covered by the faster train.
The sum is 224 miles, because they together covered all the distance to the moment when they meet each other.
1.6x + 1.6x + 16 = 224
3.2x + 16 = 224
3.2x = 224 - 16
3 2x = 208
x = 208/3.2
x = 65
Thus the speed of the slower train is 65mph, and that of the other train is 65 + 10 = 75mph
Responder:
35,2 ohm.
Explicación:
Dado:
La resistencia específica del conductor es,
La longitud del conductor es,
El área de la sección transversal del conductor es,
Sabemos que la resistencia de un conductor es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
Por lo tanto, la resistencia se puede expresar como:
Ahora, conecte los valores dados y resuelva para 'R'. Esto da,
Por lo tanto, la resistencia del conductor es de 35,2 ohm.