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2 years ago

How might atomic radius have any influence on electronegativity trends or no influence on ionizatation

1 answer:

7 0

The radius is proportional to the ionization energy.

This is because electrons are drawn closer to protons, which have opposite charges and hence cling to them, in a small-radius atom.
If the radius is bigger, the electrons on the outside edge of the atom are not as tightly bound and are therefore more easily lost, requiring less energy to ionize.
Factors are more shielding (from core electrons) in the lowest elements of a family, allowing electrons to escape more easily. For those who are currently in a period, the effective nuclear charge grows as the period progresses (more protons, but no more energy levels, so the electrons are the same distance from the nucleus). This causes the electrons to be held closer together (smaller radius), requiring more energy to ionize them.

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Acids naturally present in food are safe to eat because they usually are..?

pantera1 [17]

Because they usually are weak.
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6 0

4 years ago

What is the mass of 1.6x1020 molecules of carbon dioxide?

valentina_108 [34]

Answer:

$1.2*10^{-2} g$

Explanation:

$1 mol - 6*10^{23} particles$

$1.6*10^{20}* \frac{1 mol}{6.02*10^{23}} = 0.00026578 mol\\\\M(CO2) = 12 + 2*32=44 \frac{g}{mol}\\$

$44\frac{g}{mol} *0.00026578 mol =0.012 = 1.2*10^{-2} g$

8 0

3 years ago

I need to measure the width of mt MP3 player what unit should i use

podryga [215]

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7 0

4 years ago

Give the percent yield when 28.16 g of CO2 are formed from the reaction of 4.000 moles of C8H18 with 4.000 moles of O2.

ludmilkaskok [199]

Answer:

Percentage yield = 25%

Explanation:

Given data:

Moles of C₈H₁₈ = 4 mol

Moles of O₂ = 4 mol

Actual yield of CO₂ = 28.16 g

Percentage yield = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25 O₂ → 16CO₂ + 18H₂O

Now we will compare the moles of CO₂ with O₂ and C₈H₁₈.

C₈H₁₈ : CO₂

2 : 16

4 : 16/2×4=32 mol

O₂ : CO₂

25 : 16

4 : 16/25×4=2.56 mol

Mass of CO₂:

Mass = number of moles× molar mass

Mass = 2.56 mol ×44 g/mol

Mass = 112.64 g

Percentage yield:

Percentage yield = Actual yield /theoretical yield × 100

Percentage yield = 28.16 g / 112.64 g× 100

Percentage yield = 0.25× 100

Percentage yield = 25%

5 0

3 years ago

Why should you avoid the flammable range for a chemical?

mina [271]

The air is too "rich" to burn above the upper limit, but the situation might soon deteriorate into danger: For instance, increasing the air in a space can quickly reduce the product's vapor percentage to levels that are within its flammability range, which could have explosive effects.

<h3>Why should we handle combustible materials carefully?</h3>

Flammable liquids and gases need to be handled and stored carefully since they have low flash points. Never assume that these items won't catch fire. You must continually keep in mind the safety precautions for handling and storing combustible products if you want to keep both you and your company safe.

<h3>What must be kept out of the vicinity of combustible chemicals?</h3>

To prevent them from getting engaged and stoking a fire, combustible objects including cardboard, paper towels, sawdust, and waste must be kept away from flammable storage spaces. All flammable liquid containers must be kept closed while not in use to further help avoid fires.

learn more about flammable chemical here

brainly.com/question/8991581

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6 0

2 years ago