Answer:
H = start height (v = 0)
h = present height
v = present speed
assuming no friction
total energy = PE + KE
mgH = mgh + .5mv^2
if PE = KE then
mgH = mgh + mgh
h = H/2
potential energy = kinetic energy when object is at half its start height.
Explanation:
Answer:
0.22 b
Explanation:
Quadrupole moment of the nucleon is,

And also,

And, 
Now,

For Bismuth
and A is 209.

Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b
Answer:heed
Explanation:
heed knows how to divide.
Answer:
1. 2.12105 J. The final kinetic energy is. KE f mv2. (875.0 kg)(44.0 m/s)2 2.What is the velocity of the two hockey players after the collision? ... A 10.0-kg test rocket is fired vertically from.
Explanation:
Sana maka tulong