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3 years ago

How can a simple machine lift a heavy load with smaller effort

Physics

2 answers:

Llana [10]3 years ago

7 0

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort

Explanation:

solniwko [45]3 years ago

6 0

Answer:

May be this will help U

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Refrigerators are usually kept at about 5∘C, while room temperature is about 20∘C. If you were to take an "empty" sealed 2-liter

expeople1 [14]

Answer:

The volume will not contract to one fourth of the original.

Explanation:

Applying Charles's Law as:

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = ?

V₂ = 2 L

T₁ = 5 °C

T₂ = 20 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (5 + 273.15) K = 278.15 K

T₂ = (20 + 273.15) K = 293.15 K

Using Charles law as:

$V_1=\frac {V_2}{T_2} \times {T_1}$

$V_1=\frac {2\ L}{293.15 K} \times {278.15 K}$

$V_1=1.8977 L$

Thus, the volume will not contract to one fourth of the original. (1/4 of 2 L is 0.5 L).

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3 years ago

Read 2 more answers

What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo

Pachacha [2.7K]

Answer:

14,300 lines per cm

Explanation:

Answer:

14,300 cm per line

Explanation:

λ400 nm to 400nm

We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ)

In this equation,

m is the order of diffraction.

λ is the wavelength of the incident light.

d is the distance separating the centers of the two slits.

θ is the angle at which the mth order would diffract.

To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.

d = mλ / sin (θ)

As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.

d = mλ / sin (θ)

d = 1 x 700nm / 1

= 700 nm

So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.

n = 1/d

= 1 / 700 x $10^{-9}$

= 1, 430,000 lines per m

= 14,300 lines per cm

<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>

5 0

3 years ago

Consider a mass-spring system. The spring has a spring constant 2.17e 3 N/m. On the end is a mass of 4.71 kg. You start at equil

Novosadov [1.4K]

Answer:

7.4 cm

Explanation:

K = 2.17 x 10^3 N/m

m = 4.71 kg

v = 1.78 m/s (It is maximum velocity)

The angular velocity

$\omega =\sqrt{\frac{k}{m}}$

$\omega =\sqrt{\frac{2.71\times 10^{3}}{4.71}}$

ω = 24 rad/s

Maximum velocity, v = ω x A

Where, A be the maximum displacement

1.78 = 24 x A

A = 0.074 m = 7.4 cm

8 0

4 years ago

How can a simple machine lift a heavy load with smaller effort​

How can a simple machine lift a heavy load with smaller effort