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n200080 [17]
3 years ago
9

How can a simple machine lift a heavy load with smaller effort​

Physics
2 answers:
Llana [10]3 years ago
7 0

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort

Explanation:

solniwko [45]3 years ago
6 0

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort.

May be this will help U

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vovangra [49]
The maximum magnitude of the net force on the box is 20 N, which is only possible if the boy and the girl pull the box together in the same direction, horizontally and parallel to the ground.
The minimum magnitude of the net force on the box is 0 N, which will occur when the boy and the girl pull the box together in the parallel but opposite direction.
If either of them pulls at an angle from the horizontal, then the magnitude of the net force will be between 0 N and 20 N.
8 0
3 years ago
what is the kinetic energy of a 1 kilogram ball is thrown into the air with an initial velocity of 3 m/sec
s344n2d4d5 [400]
Data:
m (mass) = 1 Kg
s (speed) = 3 m/s
Kinetic energy = ? (Joule)


Formula (Kinetic energy)
E_{k} =  \frac{m*s^2}{2}

Solving:
E_{k} = \frac{m*s^2}{2}
E_{k} =  \frac{1*3^2}{2}
E_{k} =  \frac{1*9}{2}
E_{k} =  \frac{9}{2}
\boxed{\boxed{E_{k} = 4.5\:J}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
Who is your greatest scientist, and what was his or her achievement? « brainliest assured»​
Anton [14]

Answer:

My greatest scientist is David Baltimore.

Explanation:

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Anybody got any answers???
dexar [7]

Answer:

b? to a?

Explanation:

6 0
3 years ago
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To determine the displacement, since we are given the potential energy, we use the equation for potential energy. For a spring, it is one-half the product of the spring constant and the square of the displacement. We do as follows:

PE = kx^2/2
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Therefore, the displacement would be 0.32 m.
7 0
3 years ago
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