Answer:
Thermospheric temperatures increase with altitude due to absorption of highly energetic solar radiation. ... Radiation causes the atmosphere particles in this layer to become electrically charged particles, enabling radio waves to be refracted and thus be received beyond the horizon.
Explanation:
Answer:
[Glycerol] = 0.0205 mol/kg
Explanation:
Molality means concentration. This sort of concentration indicated the moles of solute which are contained in 1kg of solvent.
We start from molarity which are the moles of solute, that are contained in 1L of solution.
2.05×10⁻² mol/L are contained in 1 L of solution.
We must assume, that volume of solvent is 999.1 mL so let's determine the mass of solvent, by density
999.1 mL . 0.9982 g/7mL = 997.3 g
For molality we need mass in kg, so let's convert the mass of solvent
997.3 g . 1kg /1000g = 0.9973 kg.
Molality → mol/kg → 2.05×10⁻² mol / 0.9973 kg = 0.0205 m
The required moles of AgBr precipitate produced by given moles of silver nitrate is 0.0123.
<h3>How do we calculate moles from molarity?</h3>
Molarity of any solution is define as the moles of solute present in per liter of the solution and it will be represented as:
M = n/V
Given that, molarity of AgNO₃ = 0.250M
Volume of AgNO₃ = 49.5mL = 0.0495L
Moles of AgNO₃ = (0.25)(0.0495) = 0.0123mol
Given chemical reaction is:
2AgNO₃(aq) + CaBr(aq) → 2AgBr(s) + Ca(NO₃)₂(aq)
As it is mention that CaBr is present in excess quantity and AgNO₃ is the limiting reagent so the formation of precipitate will depend on the AgNO₃.
From the stoichiometry of the reaction, it is clear that:
2 moles of AgNO₃ = produces 2 moles of AgBr
0.0123 moles of AgNO₃ = produces 2/2×0.0123=0.0123 moles of AgBr
Hence 0.0123 is the required moles of precipitate.
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<h2>Answer:</h2>
5.65moles
<h2>Explanations:</h2>
The formula for calculating the number of moles the compound contain is given as:
Given the following parameters
Mass of Ag = 700grams
Determine the molar mass of AgO
Molar mass = 107.87 + 16
Molar mass = 123.87g/mol
Determine the moles of AgO
Hence the moles of AgO present is 5.65moles
Answer : The value of equilibrium constant (K) is, 424.3
Explanation : Given,
Concentration of 
at equilibrium = 0.067 mol
Concentration of 
at equilibrium = 0.021 mol
Concentration of 
at equilibrium = 0.040 mol
The given chemical reaction is:
The expression for equilibrium constant is:
![K_c=\frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
Now put all the given values in this expression, we get:
Thus, the value of equilibrium constant (K) is, 424.3
