Answer:
Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.
Explanation:
Hello,
In this case, for the dilution process from concentrated 12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:
Which can also be written in terms of concentrations and volumes:
Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:
It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.
Best regards.
Is true. Nitrogen gas behaves more like an ideal gas as the
temperature increases. Under normal conditions such as normal pressure and temperature
conditions , most real gases behave qualitatively as an ideal gas. Many
gases such as air , nitrogen , oxygen ,hydrogen , noble gases , and some heavy
gases such as carbon dioxide can be treated as ideal gases within a reasonable tolerance. Generally,
the removal of ideal gas conditions tends to be lower at higher temperatures and lower density (that is at lower pressure ), since the work made by the intermolecular
forces is less important compared to the kinetic energy<span> of the particles, and the size of the molecules is less important
compared to the empty space between them. </span><span>The ideal gas model
tends to fail at lower temperatures or at high pressures, when intermolecular
forces and intermolecular size are important.</span>
Answer: hello attached below is the complete question
answer :
attached below
Explanation:
Diagram of the all the observed products are attached below
note: through radical mechanism The free radicals are stabilized by resonance
Attached below
Answer: 0.0274 M
Explanation:-
The balanced chemical solution is:
According to the neutralization law,
where,
= molarity of 
solution = 0.117 M
= volume of solution = 23.4 ml
= molarity of 
solution = ?
= volume of solution = 100.0 ml
= valency of = 1
= valency of = 1
Therefore, the concentration of ammonia in a solution will be 0.0274 M
