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3 years ago

15

A small chunk of wax floats if placed in water. If huge piece of wax that is as heavy as a

1 answer:

Fynjy0 [20]3 years ago

8 0

The wax would float because of its weight

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A graduated cylinder.measures 15.3 mL. Convert this measurement to DaL

ololo11 [35]

Answer:

0.000153DaL

Explanation:

We have been given:

15.3mL to convert to DaL

DaL is a unit of volume which indicates a decaliter.

This implies that;

1 Da L = 1 x 10²L

So:

1 mL = 1 x 10⁻³L

So 15.3mL will give 15.3 x 10⁻³L

So;

1 x 10²L = 1 DaL

15.3 x 10⁻³L will give $\frac{15.3 x 10^{-3} }{1 x 10^{2} }$ = 15.3 x 10⁻⁵DaL

Therefore, this is 0.000153DaL

5 0

3 years ago

Jeff of the Jungle swings on a 7.6-m vine that initially makes an angle of 32 ∘ with the vertical.

shtirl [24]

To solve this problem we will use the trigonometric concepts to find the distance h, which will allow us to find the speed of Jeff and that will finally be the variable that will indicate the total tension, since it is the variable of the centrifugal Force given in the vine at the lowest poing of the swing.

From the image:

$cos (32) = \frac{(7.6-h)}{7.6}$

$h = 1.1548m$

When Jeff reaches his lowest point his potential energy is converted to kinetic energy

$PE = KE$

$mgh = \frac{1}{2} mv^2$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.8)(1.1548)}$

$v= 4.75m/s$

Tension in the string at the lowest point is sum of weight of Jeff and the his centripetal force

$T = W+F_c$

$T = mg + \frac{mv^2}{r}$

$T = (83)(9.8)+\frac{(9.8)( 4.75)^2}{7.6}$

$T = 842.49N$

Therefore the tension in the vine at the lowest point of the swing is 842.49N

3 0

3 years ago

A tennis player tosses a tennis ball straight up and then catches it after 2.00 s at the same height as the point of release. (a

Readme [11.4K]

Answer:

Part a)

a = -9.81 m/s/s

Part b)

v = 0

Part c)

v = 9.81 m/s

Part d)

$H = 4.905 m$

Explanation:

Part a)

During the motion of ball it will have only gravitational force on the ball

so here the acceleration of the ball is only due to gravity

so it is given as

$a = g = 9.81 m/s^2$

Part b)

As we know that ball is moving against the gravity

so here the velocity of ball will keep on decreasing as the ball moves upwards

so at the highest point of the motion of the ball the speed of ball reduce to zero

$v_f = 0$

Part c)

We know that the total time taken by the ball to come back to the initial position is T = 2 s

so in this time displacement of the ball will be zero

$\Delta y = 0 = v_y t + \frac{1}{2} at^2$

$0 = v_y (2) - \frac{1}{2}(9.81)(2^2)$

$v_y = 9.81 m/s$

Part d)

at the maximum height position we know that the final speed will be zero

so we will have

$v_f^2 - v_i^2 = 2 a d$

here we have

$0 - (9.81^2) = 2(-9.81)H$

$H = 4.905 m$

4 0

3 years ago

Speed (S) of a moving object is calculated from

bonufazy [111]

Answer:distance divided by time

Explanation:

7 0

3 years ago

Read 2 more answers

The wind is blowing in the direction of a vector pointing at an angle 30 degrees to the east of due north, at 35 miles/hour. An

a_sh-v [17]

Answer:

Time for the first plane to cover 1 degree of latitude is 0.2hour

Time for the second plane to cover 1 degree of latitude is 0.203hour

Explanation:

Check attachment for solution

6 0

4 years ago