Solution :
Given :

Operation time,
= 3000 hours per year

Operation time,
= 2000 hours per year
The density, ρ = 
The wind blows steadily. So, the K.E. = 

The power generation is the time rate of the kinetic energy which can be calculated as follows:
Power = 
Regarding that
. Then,
Power
→ Power = constant x 
Since,
is constant for both the sites and the area is the same as same winf turbine is used.
For the first site,
Power, 

For the second site,
Power, 
I think it’s is false I’m not that sure
Answer:
hello your question is incomplete attached below is the complete question
answer: There is a hydraulic jump
Explanation:
First we have to calculate the depth of flow downstream of the gate
y1 =
----------- ( 1 )
Cc ( concentration coefficient ) = 0.61 ( assumed )
Yg ( depth of gate opening ) = 0.5
hence equation 1 becomes
y1 = 0.61 * 0.5 = 0.305 m
calculate the flow per unit width q
q = Q / b ----------- ( 2 )
Q = 10 m^3 /s
b = 2 m
hence equation 2 becomes
q = 10 / 2 = 5 m^2/s
next calculate the depth before hydraulic jump y2 by using the hydraulic equation
answer : where y1 < y2 hence a hydraulic jump occurs in the lined channel
attached below is the remaining part of the solution