1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natasha_Volkova [10]
3 years ago
5

Suggest appropriate materials for a cylinder head and give four reason for your choice​

Engineering
1 answer:
ycow [4]3 years ago
7 0

Answer:

head and give four reason for your choice

You might be interested in
Technician A says that the carpet padding is designed to help reduce noise and vibrations.
Firdavs [7]

Answer:

Technicians A is right for the answer

4 0
3 years ago
Water is boiled in a pot covered with a loosely fitting lid at a location where the pressure is 85.4 kPa. A 2.61 kW resistance h
eimsori [14]

Answer:

t = 6179.1 s = 102.9 min = 1.7 h

Explanation:

The energy provided by the resistance heater must be equal to the energy required to boil the water:

E = ΔQ

ηPt = mH

where.

η = efficiency = 84.5 % = 0.845

P = Power = 2.61 KW = 2610 W

t = time = ?

m = mass of water = 6.03 kg

H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg

Therefore,

(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)

t = \frac{1.362\ x\ 10^7\ J}{2205.45\ W}

<u>t = 6179.1 s = 102.9 min = 1.7 h</u>

4 0
2 years ago
96/64 reduced to its lowest term
Marina CMI [18]

Answer:

3/2

Explanation:

8 0
2 years ago
The modulus of elasticity for a ceramic material having 6.0 vol% porosity is 303 GPa. (a) Calculate the modulus of elasticity (i
Phantasy [73]

Answer:

modulus of elasticity for the nonporous material is 340.74 GPa

Explanation:

given data

porosity = 303 GPa

modulus of elasticity = 6.0

solution

we get here  modulus of elasticity for the nonporous material Eo that is

E = Eo (1 - 1.9P + 0.9P²)    ...............1

put here value and we get Eo

303 = Eo ( 1 - 1.9(0.06) + 0.9(0.06)² )  

solve it we get

Eo = 340.74 GPa

8 0
3 years ago
Air is saturated with water vapor at 35.0 oC and a total pressure of 1.50 atmospheres. If the molar flow rate of the dry air in
Marizza181 [45]

Answer:

11.541 mol/min

Explanation:

temperature = 35°C

Total pressure = 1.5 * 1.013 * 10^5 = 151.95 kPa

note : partial pressure of water in mixture = saturation pressure of water at T = 35°c )

from steam table it is = 5.6291 Kpa

calculate the mole fraction of H_{2}o ( YH_{2}o )

= 5.6291 / 151.95

= 0.03704

calculate the mole fraction of air ( Yair )

 = 1 - mole fraction of water

= 1 - 0.03704 = 0.9629

Now to determine the molar flow rate of water vapor in the stream

lets assume N = Total molar flow rate

NH_{2}o = molar flow rate of water

Nair = molar  flow rate of air = 300 moles /min

note : Yair * n = Nair

therefore n = 300 / 0.9629 = 311.541  moles /min

Molar flowrate of water

=  n -  Nair

= 311.541 - 300 = 11.541 mol/min

4 0
3 years ago
Other questions:
  • The town of Mustang, TX is concerned that waste heat discharged from a new up- stream power plant will decimate the minnow popul
    10·1 answer
  • An insulated piston-cylinder device contains 5 L of saturated liquid water at a constant pressure of 175 kPa. Water is stirred b
    9·1 answer
  • What's a disadvantage of highest MERV-rated filters?
    10·2 answers
  • the frequencies 10, 12, 23 and 45 Hz. (a) What is the minimum sampling rate required to avoid aliasing? (b) If you sample at 40
    13·1 answer
  • Structural engineers use wireless sensor networks to monitor the condition of dams and bridges.
    9·1 answer
  • Which of the following identifies one factor that causes conventional tillage to actually be good for the environment?
    7·1 answer
  • Is the MI-24 Hind the most widely exported combat helicopter in the world?
    14·1 answer
  • Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
    9·1 answer
  • What do Engineering Systems achieve?
    8·1 answer
  • Architecture reflects multidisciplinary
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!