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2 years ago

5

How does wind affect the amount of rain? 3 or sentence

1 answer:

neonofarm [45]2 years ago

8 0

When winds in the upper troposphere blow away from one another instead (diverge), they form an area of lower pressure up high.
That lower pressure sucks air up from below, causing lower pressure at ground level.
The air that sinks in a high is dry, and you need moist air to make rain.
It blows the heavy dark clouds filled with water over to other areas which brings rain.

Explanation:

<h3>Hope it helps you!!</h3>

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Which of the following happens to an object in uniform circular motion?

podryga [215]

Answer:

As an object moves in a circle, it is constantly changing its direction. ... Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed.

5 0

4 years ago

Assuming that the limits of the visible spectrum are approximately 380 and 700 nm, find the angular range of the first-order vis

ch4aika [34]

Answer:

angular range is ( 0.681 rad , 0.35 rad )

Explanation:

given data

wavelength λ = 380 nm = 380 × $10^{-9}$ m

wavelength λ = 700 nm = 700 × $10^{-9}$ m

to find out

angular range of the first-order

solution

we will apply here slit experiment equation that is

d sinθ = m λ ...........1

here m is 1 for single slit and d is = $\frac{1}{900*10^3 m}$

so put here value in equation 1 for 380 nm

we get

d sinθ = m λ

$\frac{1}{900*10^3}$ sinθ = 1 × 380 × $10^{-9}$

θ = 0.35 rad

and for 700 nm

we get

d sinθ = m λ

$\frac{1}{900*10^3}$ sinθ = 1 × 700 × $10^{-9}$

θ = 0.681 rad

so angular range is ( 0.681 rad , 0.35 rad )

3 0

4 years ago

What are the opposite ends of a magnet called? A. north and south terminals B. north and south poles C. magnetic fields D. magne

Bezzdna [24]

I think the answer is B.

Hope this helps.

6 0

3 years ago

Read 2 more answers

A bowling ball moving with a velocity of 5V to the right collides elastically with a beach ball moving at a velocity 2V to the l

katen-ka-za [31]

Answer:

$v'_2=3V$

Explanation:

From the question we are told that:

Bowling ball Speed $v_1=5 m/s$

Beach ball Speed $v_2=2 m/s$

Let The Mass be equal i.e

$M_1=M_2$

Therefore

Generally the equation for Velocity of beach ball after collision $v'_2$ is mathematically given by

Since Velocity is Vector Quantity

Therefore

$v'_2=v_1-v_2$

$v'_2=5-2$

$v'_2=3V$

3 0

3 years ago

A piano tuner sounds two strings simultaneously. One has been previously tuned to vibrate at 293.0 Hz. The tuner hears 3.0 beats

ololo11 [35]

Answer:

Part a)

$f_B = 290 Hz$

Part B)

percentage increase is

$percentage = 1.38$ %

Explanation:

Part a)

As we know that the beat frequency is

$f_A - f_B = 3$

after increasing the tension the beat frequency is decreased and hence the tension in string B will increase

So we have

$293 - f_B = 3$

$f_B = 290 Hz$

Part B)

percentage increase in the tension of the string will be given as

$f_A - f_B' = 1$

$f_B' = 292 Hz$

now we have

$f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}$

so we have

$T_1 = C (290)^2$

$T_2 = C(292)^2$

so we have

$\frac{\Delta T}{T} = \frac{292^2 - 290^2}{290^2}$

percentage increase is

$percentage = 1.38$

4 0

4 years ago