The surface area expressed in square feet of a single face of a pile is 1.45 square feet.
<u>Explanation:</u>
The dimensions of the pillar are given as 14 in 
14 in
(1 feet = 12 inch)
According to the pillar dimensions mentioned in the problem, the length of the pillar should be 15 inches, height by 14 inches and the width by 14 inches.
There will be two surface areas of the concrete pile, one implies side surface area and the other is end surface area.
For calculating the side surface area,
Area of the side surface = 14 in 15 in
= 
= 1.16 1.25
= 1.45 square feet.
(In the given question, only a single face is asked so there is no need to find the surface area of the end face.)
The balanced equation is Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag
Step 1. Write the <em>unbalanced equation
</em>
Mg + AgNO₃ ⟶ Mg(NO₃)₂ + Ag
Step 2. Start with the<em> most complicated-looking formula</em> [Mg(NO₃)₂] and balance its atoms.
Mg: Already balanced —1 atom each side.
N: We need 2 N on the left. Put a 2 in front of AgNO₃.
1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + Ag
O: Already balanced —6 atom6 each side.
Step 3: Balance <em>Ag</em>
We have 2Ag on the left. We need 2Ag on the right.
1Mg + 2AgNO₃ ⟶ 1Mg(NO₃)₂ + 2Ag
First convert celcius to Kelvin.
20 + 273 = 293K
31 + 273 = 304K
Now we can set up an equation based on the information we have.
V1 = 5
P1 = 365
T1 = 293
V2 = 5
P1 = x
T2 = 304
The equation be: 
Now just solve.
1825/293 = 5x/304
Cross multiply.
554800 = 1465x
Divide both sides by 1465
x = 378.7030717 which can then be rounded to 378.7 mmHg
D sublevel because the s sublevel has one orbital, the p sublevel has three orbitals, the d sublevel has five orbitals, and the f sublevel has seven orbitals. In the first period, only the 1s sublevel is being filled.
Temperature <span>is a measure of the average kinetic energy of particles, not just gas. </span>
