WILL GIVE BRAINLIEST
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<u>Answer:</u> The equilibrium concentration of ICl is 0.27 M
<u>Explanation:</u>
We are given:
Initial moles of iodine gas = 0.45 moles
Initial moles of chlorine gas = 0.45 moles
Volume of the flask = 2.0 L
The molarity is calculated by using the equation:
Initial concentration of iodine gas =
Initial concentration of chlorine gas =
For the given chemical equation:
As, the initial moles of iodine and chlorine are given. So, the reaction will proceed backwards.
The chemical equation becomes:
<u>Initial:</u> 0.225 0.225
<u>At eqllm:</u> 0.225-x 0.225-x 2x
The expression of for above equation follows:
Putting values in above equation, we get:
Neglecting the value of x = 0.668 because equilibrium concentration cannot be greater than the initial concentration
So, equilibrium concentration of ICl = 2x = (2 × 0.135) = 0.27 M
Hence, the equilibrium concentration of ICl is 0.27 M