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Tasya [4]
2 years ago
12

PLEASE HELP

Chemistry
1 answer:
Anarel [89]2 years ago
5 0

Answer:

The element with electron configuration 1s² 2s² 2p⁶ will most likely not react with an element having seven Valence electrons.

The electron configuration of the element in discuss is 1s² 2s² 2p⁶.

The element has enough electrons to fill it's energy level, n = 2 shell.

In essence, the element in discuss is unreactive as it has attained it's octet configuration and as such is neither in need of an electron nor ready to donate an electron.

As such, although an atom having seven Valence electrons is highly electronegative and as such is an electron attractor, the element with the full octet configuration does not react with it.

This unreactive nature of noble gases is attributed to the full octet configuration of noble gases.

P.S: The electron configuration above is the electron configuration of Neon, Ne.

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Q3. Which of the following objects are chiral and which are achiral? a
Sergio039 [100]

Answer:

See explanation

Explanation:

In this question, we have to follow the IUPAC rules. Lets analyze each compound:

a. 1-methylbutane

In this compound we have a chain of 5 carbons, so the correct name is <u>Pentane.</u>

b. 1,1,3-trimethylhexane

In this compound, we longest chain is made of 7 carbons, so, we have to use the name "heptane". Carbon one would be the closet one to the methyl group, so the correct name is  <u>2,4-dimethylheptane.</u>

c. 5-octyne

In this case, carbon 1 would be the closet one to the triplet bond. With this in mind, the correct name is <u>oct-3-yne.</u>

d. 2-ethyl-1-propanol

In this compound, we longest chain is made of 4 carbons, so, we have to use the name "butane". Carbon one would be the carbon with the "OH" group, so the correct name is  <u>2-methylbutan-1-ol.</u>

<u>e. 2.2-dimethyl-3-butanol</u>

In this case, carbon 1 would be the closet one to the "OH". With this in mind, the correct name is <u>3,3-dimethylbutan-2-ol.</u>

See figure 1

I hope it helps!

3 0
4 years ago
Convert 7.89 x 10^8 molecules of water to liters.
NNADVOKAT [17]

Answer:

2.94 x 10⁻¹⁴L

Explanation:

To solve this problem, we have to assume that the condition of this water is at standard temperature and pressure, STP.

At STP;

       1 mole of gas have a volume of 22.4L

So, let us find the number of moles of this water first;

         6.02 x 10²³ molecules can be found in 1 mole of a substance

          7.89 x 10⁸ molecules will contain \frac{7.89 x 10^{8} }{6.02 x 10^{23} }   = 1.31 x 10⁻¹⁵mole of water

So;

        Volume of water  = 22.4 x 1.31 x 10⁻¹⁵  = 2.94 x 10⁻¹⁴L

5 0
3 years ago
Adding what two values gives the mass of an atom?
Eduardwww [97]
The protons and neutrons
8 0
3 years ago
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jok3333 [9.3K]
4 th one is Midwest direction. Found from visible paragraph. Pls apload the content to answer
5 0
3 years ago
Secondary amines react with the nitrosonium ion to generate ________. n-nitrosoamines diazonium salts anilines imines oximes
katen-ka-za [31]
Answer:
             Secondary amines react with the nitrosonium ion to generate <span><u>N-Nitrosoamines</u>.

Explanation:
                   Nitosonium Ion is generally utilized in the formation of Diazonium Salts which are considered excellent starting Material from synthesis point of View. Diazonium salts are formed by reacting Primary Amine or Anilines with Nitrosonium Ions. In our case, the Amine given is Secondary. So, reaction of <em>Sec.</em> Amines with Nitrosonium Ions stops after the formation of N-Nitrosoamine as there is no Hydrogen attached to Nitrogen atom of Amine to be eliminated and form a double and eventually triple bond with the Nitrogen atom of Nitrosonium Ion.</span>

7 0
3 years ago
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