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KonstantinChe [14]
3 years ago
6

Which of the following tools measures weight? A balance A scale A cyclometer A graduated cylinder

Physics
1 answer:
Kazeer [188]3 years ago
8 0
I'm pretty sure its a scale.
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If the ball is 0.60 mm from her shoulder, what is the tangential acceleration of the ball? This is the key quantity here--it's a
PolarNik [594]

This question is incomplete, the complete question is;

In a softball windmill pitch, the pitcher rotates her arm through just over half a circle, bringing the ball from a point above her shoulder and slightly forward to a release point below her shoulder and slightly forward. (Figure 1) shows smoothed data for the angular velocity of the upper arm of a college softball pitcher doing a windmill pitch; at time t = 0 her arm is vertical and already in motion. For the first 0.15 s there is a steady increase in speed, leading to a final push with a greater acceleration during the final 0.05 s before the release. In each part of the problem, determine the corresponding quantity during the first 0.15 s of the pitch.

Angular Velocity at time 0s = 12 rad/s

Angular Velocity at time 0.15s = 24 rad/s

a) What is the angular acceleration?

b) If the ball is 0.60 m from her shoulder, what is the tangential acceleration of the ball? This is the key quantity here--it's a measure of how much the ball is speeding up. Express your answer in m/s2 and in units of g

Answer:

a) the angular acceleration is 80 rad/s²

b) the tangential acceleration of the ball is;

- a = 48 m/s²

- a = 4.9 g

Explanation:

Given the data in the question;

from the graph below;

Angular Velocity at time 0s w_o = 12 rad/s

Angular Velocity at time 0.15s w_f = 24 rad/s

a) What is the angular acceleration;

Angular acceleration ∝ = ( w_f - w_o ) / dt

we substitute

Angular acceleration ∝ = ( 24 - 12 ) / 0.15

Angular acceleration ∝ = 12 / 0.15

Angular acceleration ∝ = 80 rad/s²

Therefore, the angular acceleration is 80 rad/s²

b)

If the ball is 0.60 m from her shoulder, i.e s = 0.6 m

the tangential acceleration of the ball will be;

a = ∝ × s

we substitute

a = 80 × 0.6

a = 48 m/s²

a = ( 48 / 9.8 )g

a = 4.9 g

Therefore, the tangential acceleration of the ball is;

- a = 48 m/s²

- a = 4.9 g

8 0
3 years ago
Which of the following STEM discoverers is known for inventing the circular saws used in sawmills? Babbitt Edison Gates Hawking
Jet001 [13]
Among the STEM discoverers, the one who is known for the invention of the circular saws that are used in sawmills is Babbitt or better known as Sarah "Tabitha<span>" Babbitt, an American inventor and Shaker tool maker. The answer to this is the first option. Hope this helps.</span>
5 0
3 years ago
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Mandeep climbs up a 10 meter ladder with a force of 4 Newtons in 20 seconds. What is his power output?
cupoosta [38]

Explanation:

Work Done = Force * Displacement

= (4N)(10m) = 40J.

Power = Work Done / Time

= (40J)/(20s) = 2J/s = 2 Nm/sec.

6 0
3 years ago
If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent
Zina [86]

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

= 30*10^-3A x 100*10^3v

= 3000watts

3 0
3 years ago
A moose runs through the woods and covers 825 m North in 118 s. What is the average velocity of the moose?
weqwewe [10]
  • Total displacement=825m
  • Total Time=118s

Average Velocity=Total Displacement/Total Time

\\ \sf\longmapsto Average\: Velocity=\dfrac{825}{118}

\\ \sf\longmapsto Average\:Velocity\approx 8m/s

4 0
2 years ago
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