Answer and Explanation
The isomer picked is the N-Propylamine.
It has a lone pair of electron available on the electron rich Nitrogen and no formal charge.
Since it will be hard to draw the Lewis structure in this answer format, I'll attach a picture of the Lewis structure to this answer.
The lone pair of electron is shown by the two dots on the Nitrogen atom.
Answer:
C, 3.00 moles
Explanation:
First, balance the equation.
4Al + 3O2 ---> 2Al2O3
From the balanced equation, assuming Al is limiting, the mole ratio of Al:Al2O3 = 4:2 = 2:1,
meaning every 2 moles of Al used, produces 1 mole of Al2O3.
So, since 1.5 moles of Al2O3 is produced,
the no. of moles of Al used = 1.5 x2
= 3.0 moles
= C
Answer:
The answers are:
Purines:
C. contain four ring nitrogen atoms.
E. contain two heterocyclic rings.
Pyrimidines:
C. contain only two ring nitrogen atoms.
E. contain one heterocyclic ring.
Explanation:
Purines and Pyrimidines are nitrogenous bases which are the building blocks of nucleic acids (DNA and RNA).
<u>Purines</u> are composed by two fused heterocyclic rings, one of them is a 6-ring and the other is a 5-ring. Each ring contains two nitrogen atoms which form part of the ring. Thus, the nitrogen positions in purines are: 1', 3', 7' and 9'. Depending on the functional groups bonded to the two-ring structure, a purine base can be Guanidine (G) or Adenine (A).
The structure of <u>Pyrimidines</u> is a single heterocycle ring wich contains two nitrogen atoms in positions 1' and 3'. Depending of the functional groups, they can be: Cytosine (C), Thymidine (T) and Uracil (U, which is found in RNA).
The number of liters of 0.90% NaCl solution one can make from 470 milligrams of table salt is 52.22 mL (milliliters) or 0.0522 L (liters)
In order to determine volume (number of liters) one can make from 470 milligrams of table salt (NaCl)
First, we will convert the unit of concentration to grams per liter or grams per milliliter
From the question, the desired concentration is 0.90% NaCl (9 grams of salt per 1000 grams of solution)
Since the density of the NaCl solution is 1.0 g solution/mL solution, then
9 grams of salt per 1000 grams of solution means 9 grams of salt per 1000 mL of solution.
From the question, mass of the table salt = 470 milligrams = (470/1000) grams
∴ Mass of the table salt = 0.47 grams
Now,
If there are 9 grams of salt per 1000 mL of solution
Then, there will be 0.47 grams per mL of solution
∴ mL
mL
mL
mL
∴ There will be 0.47 grams per 52.22 mL of solution
Hence, the number of liters of 0.90% NaCl solution one can make from 470 milligrams of table salt is 52.22 mL (milliliters) or 0.0522 L (liters)
Learn more here: brainly.com/question/11877033
Answer:
K = Ka/Kb
Explanation:
P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?
P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka
PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb
K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)
Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)
Kb = [PCl₅]/ ([PCl₃] [Cl₂])
Since [PCl₅] = [PCl₅]
From the Ka equation,
[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)
From the Kb equation
[PCl₅] = Kb ([PCl₃] [Cl₂])
Equating them
Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])
(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)
(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)
Comparing this with the equation for the overall equilibrium constant
K = Ka/Kb