Answer:
Not sure
Step-by-step explanation:
Sorry
The answer to how many times can 4 go into 110 is 27.5
Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams
Answer:
5√2
Step-by-step explanation:
√8 + √18
We first have to find what is the largest perfect square that goes into √8:
4 is the largest, so therefore → √8 gives you 2√2:
Work: √4 * √2 → 2 * √2 → 2√2
Now we have to find what is the largest perfect square that goes into √18:
9 is the largest, so therefore → √18 gives you 3√2:
Work: √9 * √2 → 3 * √2 → 3√2
Because 2√2 and 3√2 have the same "base" of √2, they can be added together:
2√2 + 3√2 = 5√2 (The "bases" are to be left alone!)
Answer:
2^x
64 bacterium
10 hours
Step-by-step explanation:
doubles every hour
if x = hours
2^x
2^x --> 2⁶ = 64
2^x = 1024
1024 = 2^10 ---> x=10
