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Romashka [77]
3 years ago
6

Which of the following is not a reason fluorescent lamps are advantageous over incandescent lamps?

Physics
2 answers:
aleksklad [387]3 years ago
5 0
The right answer for the question that is being asked and shown above is that: "C. Fluorescent lamps dissipate more energy as light instead of heat than incandescent lamps." This<span> is not a reason fluorescent lamps are advantageous over incandescent lamps.</span>
cricket20 [7]3 years ago
4 0

Answer;

B. Fluorescent lamps operate at a higher temperature than incandescent lamps.

Explanation;

-A fluorescent lamp, is a type of electric light (lamp) that uses ultraviolet emitted by mercury vapor to excite a phosphor, which emits visible light.

-A fluorescent lamp produces less heat, thus, it is much more efficient. A fluorescent bulb can produce between 50 and 100 lumens per watt. This makes fluorescent bulbs four to six times more efficient than incandescent bulbs.

-Fluorescent lamps operate best around room temperature. At much lower or higher temperatures, efficacy decreases.

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A water tank is in the shape of an inverted cone with depth 10 meters, and top radius 8 meters. Water is flowing into the tank a
Elis [28]

Answer:

The value of leaking rate in the question is repeated. By searching on the web I could find the correct value wich is 0.002h^2 m^3 /min.

The depth of the water has to be equal to 7.07 m in order to have a stationary volume.

Explanation:

In order to have a stationary water level the flow of water that comes into the tank (0.1 m^3/min) must be equal to the flow of water that goes out of the tank (0.002*h^2 m^3/min), therefore:

0.002*h^2 = 0.1

h^2 = 0.1/0.002

h^2 = 50

h = sqrt(50) = 7.07 m

7 0
3 years ago
The acceleration due to gravity of the moon is 1.67
Karo-lina-s [1.5K]

Answer:

I think it's 1.625 m/s2

5 0
3 years ago
Air at 30°C and 2MPa flows at steady state in a horizontal pipeline with a velocity of 25 m/s. It passes through a throttle valv
erastovalidia [21]

Answer:

V_2=159.9\ m/s

T_2=290.6K

Explanation:

At initial condition

P=2 MPa

T=30°C

V=25 m/s

At final condition

P=0.3 MPa

Now from first law for open system

h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}

We know that for air

h= 1.010 x T  KJ/kg

1.01\times 303+\dfrac{25^2}{2000}=1.01\times T+\dfrac{V_2^2}{2000}                               -----1

Now from mass balance

\rho_1A_1V_1=\rho_2A_2V_2

We also know that

\rho=\dfrac{P}{RT}

\dfrac{P_1}{RT_1}V_1=\dfrac{P_2}{RT_2}V_2

\dfrac{2}{R\times 303}\times 25=\dfrac{0.3}{RT_2}V_2

T_2=1.81V_2                  ----------2                                                                                                

Now from equation 1 and 2

V_2^2+3673.749V-612916.49=0

So we can say that

V_2=159.9\ m/s

This is the outlet velocity.

Now by putting the values in equation 2

T_2=1.81\times 159.9  

T_2=290.6K

This is the outlet temperature.

4 0
4 years ago
Blank is the the decrease in a materail's volume when it's blank decrease ​
natulia [17]

Answer:

Explanation:

becAUSE IT POOOPYES

7 0
3 years ago
A sled is being pulled along a horizontal surface by a horizontal force F of magnitude 600 N. Starting from rest, the sled speed
Simora [160]

Answer:

1440 W

Explanation:

First of all, we can find the total displacement of the sled, which is given by

d=\frac{1}{2}at^2

where

a = 0.08 m/s^2 is the acceleration

t = 1 min = 60 s is the time

Substituting,

d=\frac{1}{2}(0.08 m/s^2)(60 s)^2=144 m

Now we can find the wotk done on the sled, equal to the product between force and displacement:

W=Fd=(600 N)(144 m)=86,400 J

And finally we can fidn the average power, which is the ratio between the work done and the time taken:

P=\frac{W}{t}=\frac{86,400 J}{60 s}=1440 W

6 0
3 years ago
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