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ozzi
3 years ago
9

Would Lithium and Fluoride still be neutral?explain in 2-3 sentences

Chemistry
1 answer:
Fed [463]3 years ago
6 0

Answer:

LiF (lithium fluoride)

Explanation:

Lithium ions have a charge of +1 and fluoride ions have a charge of -1. The formula unit for lithium fluoride is LiF, which means that the lithium and fluoride ions are present in a 1:1 ratio. So the positive and negative charges cancel each other, and the compound lithium fluoride is neutral.

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What is the chemical formula for coper(ll)hydroxide?
kaheart [24]
The chemical formula is Cu(OH)2
3 0
3 years ago
Covalent solutes are considered non-electrolytes. What does this mean for the conductivity of the solution?
Mashutka [201]

Answer:

Non-electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.

Explanation:

3 0
3 years ago
4 Nitrogen monoxide reacts with oxygen like this:
olga2289 [7]

a. mol O₂=0.5

b. volume O₂ = 25 cm³

c. i. the total volume of the two reactants = 75 cm³

c. ii. the volume of nitrogen dioxide formed = 50 cm³

<h3>Further explanation</h3>

Reaction

2NO(gas) + O₂(gas) ⇒ 2NO₂ (gas)

a.

mol NO = 1

From the equation, mol ratio NO : O₂ = 2 : 1, so mol O₂ :

\tt \dfrac{1}{2}\times 1=0.5

b.

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

Because mol ratio NO : O₂ = 2 : 1, so volume O₂ :

\tt \dfrac{1}{2}\times 50~cm^3=25~cm^3

c.

i. total volume of reactants : 25 cm³+ 50 cm³=75 cm³

ii. the volume of nitrogen dioxide formed :

mol ratio NO : NO₂ = 2 : 2, so volume NO₂ = volume NO = 50 cm³

6 0
3 years ago
Find the percent composition of lead in lead (II) nitrate. round to 2 significant figures.​
just olya [345]

Answer/Explanation:

62.559%

mass of an element   X 100%

mass of the compound

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

5 0
3 years ago
SUPPLEMENTARY QUESTION
sergiy2304 [10]

Answer:

850 Calories.

Explanation:

The following data were obtained from the question:

Mass (M) = 50 g

Initial temperature (T1) = 20 °C

Final temperature (T2) = 37 °C

Specific heat capacity (C) of water = 1 cal/g°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature of water.

This can be obtained as follow:

Initial temperature (T1) = 20 °C

Final temperature (T2) = 37 °C

Change in temperature (ΔT) =..?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 37 – 20

Change in temperature (ΔT) = 17 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 50 g

Specific heat capacity (C) of water = 1 cal/g°C.

Change in temperature (ΔT) = 17 °C

Heat absorbed (Q) =..?

Q = MCΔT

Q = 50 x 1 x 17

Q = 850 Calories

Therefore, the heat absorbed is 850 Calories.

3 0
4 years ago
Read 2 more answers
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