PH is the test of acidity or basicity of a solution. it follows the formula:
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case.
By literature, Ka of HF is 3.5*10^-4
<span>pKa= -log(Ka)=</span><span> 3.46 </span>
<span>pH = pKa + log [NaF / [HF] </span>
4.05 = 3.46 + log [NaF / [HF]
log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
Answer:
2H+(aq) + 20H(aq) → H20(l)
Explanation:
The reaction between sulphuric acid and calcium hydroxide is a neutralization reaction. Neutralization reaction involves the reaction of hydrogen ions and hydroxide ions to form water. This has been shown in the equation.
The number of water molecules formed depends on the number of moles of hydrogen and hydroxide ions present in the compounds. There are two hydrogen ions in sulphuric acid and two hydroxide ions in calcium hydroxide. Hence, two moles of water is formed.
Answer:
Cr
Explanation:
Cr will displace Sn from compound because Cr is higher than Sn in the electrochemical series of metals
Answer:
Sulphur (S)
Explanation:
F2 + H2S ¬¬¬> S+2HF
As we have 2 F and 2 H, they combine to form 2HF. We are left with S only