3 years ago

What is the surface area of the shape?

Physics

1 answer:

AfilCa [17]3 years ago

4 0

Answer:

162 should be the answer because 18x3x3=162.

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What is the elastic potential energy of a spring that is compressed a distance of 0.35 m and has a spring constant of 71.8 N/m?

Vitek1552 [10]

Answer:

P.E = 4.398 Joules.

Explanation:

Given the following data;

Spring constant, k = 71.8N/m

Displacement, x = 0.35m

To find the elastic potential energy;

The elastic potential energy of an object is given by the formula;

$P.E = \frac {1}{2}kx^{2}$

Substituting into the equation, we have;

$P.E = \frac {1}{2}*71.8 *(0.35)^{2}$

$P.E = 35.9 * 0.1225$

Elastic potential energy = 4.398 Joules.

<em>Therefore, the elastic potential energy of the spring is 4.398 Joules. </em>

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Answer:

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Explanation:

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VARVARA [1.3K]

An example you could use for this would be if you threw a pencil across the room 10m away. the pencil would have travelled 10m(N). you could determine the objects speed by using the formula speed=distance/time. you would have had to time how long it took for the pencil to hit the 10m marking and divide 10 by however many seconds it took.

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