the process of changing one form of energy into another
The answer is
<span>2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g)
Your answer is not yet balanced because you have 3 oxygen atoms. it should be balanced by multiplying both side by 2 such as the balanced equation I made. To check it, I will explain why your answer is not yet balanced.
check: (from your equation)
</span> 1-Pb-1
1-S-1
2 -O-3
the difference between the reactant and the product of Oxygen will prove that it is not yet balanced.
If you use 2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g), to check it:
2-Pb-2
2-S-2
6 -O-6
then this is now balance
It should be noted that bond A has greater energy because C. The atoms in bond A are held more tightly together than the atoms in bond B.
<h3>Bond</h3>
The relationship between the bond energies of nitrogen, iodine, and fluorine gases is that the bond in nitrogen gas is the most difficult to break.
From the information given, the molecule with the greatest bid energy is CH4. The bind energy measures the bond strength that the chemical bond has.
Also, the bond energy of the reactants in reaction 1 is greater than the bond energy of the reactants in reaction 2. Due to this, reaction 1 requires a greater input of energy than reaction 2.
Lastly, the difference in the bond energy of Chlorine and Bromine is that Bromine has more electron levels than chlorine.
Learn more about bonds on:
brainly.com/question/819068
Answer:
No of molcules(N)= 1.98×10^22
Explanation:
m=5.5, Mm= 167, NA= 6.02×10^23
Moles(n)= m/M= N/NA
5.5/167 = N/6.02×10^23
SIMPLIFY
N=1.98×10^22molecules
