Answer:
0.0305mol
Explanation:
CaCO3 ---> CaO + CO2
Mass of CaCO3 mol = 40 + 12 + (16 x 3) = 100g/mol
Number of CaCO3 moles heated = 3.05/100 = 0.0305 mol
One CaCO3 mol produces 1 mol CO2
Therefore 0.0305mol of CO2 produced.
Answer:
Bottle is sitting on the shelf for 15 days.
Explanation:
Given data:
Co-60 half life = 5 days
Total amount = 30.0 g
Amount left = 3.75 g
Time taken = ?
Solution:
AT time zero = 30 g
AT first half life= 30g /2 = 15 g
At 2nd half life = 15 g/ 2 = 7.5 g
At 3rd half life = 7.5 g/2 = 3.75 g
Now we will calculate the sitting time of bottle.
Half life = Time taken / number of half lives
3× 5 days = time taken
Time taken = 15 days
Bottle is sitting on the shelf for 15 days.
The answers are as follows,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr
<u>Explanation:</u>
All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.
It can be expressed as follows,
P1V1 = P2V2
Rearranging the above expression, we get,
1) The first case can be solved as,
2) The second case can be solved as,
3) The third case can be solved as,
Thus the answers for all the three cases are found as,
1. 4.71 L,
2. 3.29 L,
3. 1634.6 torr respectively
Answer:
A.
B.
Explanation:
Hello!
In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:
Thus we proceed as follows:
A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:
Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:
B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:
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