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2 years ago

Which example is an endothermic process?

Chemistry

1 answer:

galben [10]2 years ago

8 0

Answer:

I guess it is

A.) thawing frozen shrimp

Hope this helps!!!!

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Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The

Maksim231197 [3]

Answer:

$\large\boxed{\large\boxed{24.6kJ}}$

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

$Q=m\times C\times \Delta T$

m = 10.1g

C = 4.18g/JºC

ΔT = 100ºC - 55ºC = 45ºC

$Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J$

<u>2. Energy to change the liquid to steam at 100ºC</u>

$L=\lambda \times n$

λ = 40.6kJ/mol

n = 10.1g / 18.015g/mol = 0.5606mol

$L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J$

<u>3. Total energy</u>

$1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ$

7 0

3 years ago

Why do scientists share the results of experiments

VladimirAG [237]

this way they can make sure that the experiment is correct.

3 0

3 years ago

Read 2 more answers

PLZ HELP?! 50 points <br><br> Write the correct IUPAC name for the following compound

slamgirl [31]

Answer:

2-ethly-3-5 dimethylheptam

Explanation:

trust meeeeee

3 0

2 years ago

Density of a piece of wood that has a measurement of 24 cm3 and 768 g

Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 768 g

volume = 24 cm³

We have

$density = \frac{768}{24} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago

Read 2 more answers

If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised

alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}$

Solving for V₂ , we get:

3 0

3 years ago