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Flauer [41]
3 years ago
10

3. When does the iron core in an electromagnet become magnetic?​

Physics
1 answer:
rosijanka [135]3 years ago
3 0

Answer: When electricity flows through it.

Explanation:

The electromagnet exhibits magnetic properties only as soon as current flows through the nucleus. Namely, the electric current in the space around the electrical conductor through which it passes creates a magnetic field. Unlike a permanent magnet, which has a permanent property of magnetism, the electromagnet is a temporary magnet because the magnetic field also disappears when the current ceases.

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Pllssss answer thiss ...<br> its about the reading of VOLTMETER AND AMMETER
Afina-wow [57]

Answer:

The answer is C 1.8V and 0.38A

4 0
2 years ago
How do you make a magnet with wire and electricity ?
AVprozaik [17]
<h2>Answer:</h2>

<u>By wrapping the wire along a solenoid and connecting it to electricity</u>

<h2>Explanation:</h2>

If you wrap a copper wire into coils and run an electrical current through it, you will create a magnetic field. If you rotate a permanent magnet as opposed to an item that has been magnetized inside a coil of copper wire, you can create an electrical current. The strength of magnetic field generated is proportional to the amount of current through the winding.

5 0
3 years ago
If the 50 kg boy were in a spacecraft 5.0r from the center of the earth, what would his weight be?
Lady_Fox [76]
·The acceleration of gravity is proportional to

                       1 / (the square of the distance from the center) .

When we're on the surface, we're 1 radius from the center of the Earth,
and the acceleration of gravity is  9.8 m/s² .

The boy's weight = (mass) · (gravity) = (50kg) · (9.8 m/s²)

                                                             =      490 newtons .

At the distance of 5 radii from the center (4 radii altitude from the surface),
the acceleration of gravity is

                 (9.8 m/s²) · (1/5)²  =  0.39 m/s² .

The boy's weight is    (mass) · (gravity)  =  (50kg) · (0.39 m/s²)

                                                                  =     19.6 newtons .

Just as we expected, his weight at that distance is

         (19.6 / 490) = 0.04  =  1/25  =  1/5²  of his weight on the surface.
7 0
2 years ago
In a thundercloud there may be electric charges of 45.0 C near the top of the cloud and -45.0 C near the bottom of the cloud. Th
Gala2k [10]

Answer:

The electric force on the top charge is F=3.44\times 10^6\ N.

Explanation:

Given that,

Electric charges in a thundercloud, q_1=q_2=45\ C

The distance between charges, d = 2.3 km = 2300 m

Let F is the electric force on the top charge. The electric force is given by the formula as :

F=\dfrac{kq^2}{d^2}

F=\dfrac{9\times 10^9\times (45)^2}{(2300)^2}

F=3445179.58\ N

or

F=3.44\times 10^6\ N

So, the electric force on the top charge is F=3.44\times 10^6\ N. Hence, this is the required solution.                                                

7 0
3 years ago
A straight wire that is 0.60 m long is carrying a current of 2.0 A. It is placed in a uniform magnetic field of strength 0.30 T.
Degger [83]

Answer:

The angle the wire make with respect to the magnetic field is 30°

Explanation:

It is given that,

Length of straight wire, L = 0.6 m

Current carrying by the wire, I = 2 A

Magnetic field, B = 0.3 T

Force experienced by the wire, F = 0.18 N

Let θ be the angle the wire make with respect to the magnetic field. Magnetic force is given by :

F=ILB\ sin\theta

\theta=sin^{-1}(\dfrac{F}{ILB})

\theta=sin^{-1}(\dfrac{0.18\ N}{2\ A\times 0.6\times 0.3\ T})

\theta=30^{\circ}

So, the angle the wire make with respect to the magnetic field is 30°. Hence, this is the required solution.

5 0
2 years ago
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