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Lostsunrise [7]
2 years ago
5

Anyone know how to hide a body asking for a friend

Chemistry
1 answer:
Wittaler [7]2 years ago
4 0
Throw it in the ocean lol
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Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:
ankoles [38]
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds

Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)] 
                           = (945 + 2*436) - (4*390 + 240)
                            = 17 kJ/mol

The answer is 17 kJ/mol.</span>
8 0
3 years ago
Help with this question
NeTakaya
Isotope atoms mean, atoms with the same number of protons but different number of neutrons in their nuclei . The given oxygen atoms are isotopes meaning they have different number of neutrons in their nuclei . Oxygen 16 have 8 protons and 8 neutrons in its nucleus but Oxygen has 8 protons and 10 neutrons. That's what make them different.

3 0
3 years ago
Read 2 more answers
An unknown metal sulfate is found to be 72.07% SO4 2- by mass. Assuming that the charge on the metal cation is +3, determine the
wariber [46]
Lets name the unknown metal as M. Cation would be M³⁺.
the molecular formula of the compound is M₂(SO₄)₃
the mass of one mole - (molar mass of M x2 + 3 x molar mass of SO₄²⁻)
                                   = 2M + 96 x 3
                                   = 2M + 288
In 1 mol if there's 72.07% of sulphate , 
then 72.07 % corresponds to 288 g
               1 % is then      - 288/72.07 
       100 %  of the compound - 288/72.07 x 100 
 molar mass of the compound - 399.6 g/mol
mass of 2M - 399.6 - 288 = 111.6 g
molar mass of M - 111.6 /2 = 55.8 g/mol
the element with molar mass of 55.8 is Fe.
Unknown metal is iron(III) , Fe³⁺

8 0
3 years ago
Lead (ll) nitride+ammonium sulfate &gt; lead(ll) sulfate + ammonium nitride
Alenkinab [10]

Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: Pb_3N_2.

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

4. Ammonium nitride would require three amonium cations to balance the nitride anion: (NH_4)_3N.

Let's write the balanced equation:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

7 0
3 years ago
Sodium hydroxide +HCI ➙ sodium chloride +H2O<br><br> Is this a:
Alexus [3.1K]
Neutralization reaction??
4 0
3 years ago
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