Answer:
Explanation:
Hello,
In this case, we use the ideal gas equation to compute the volume as shown below:
Nonetheless we are given mass, for that reason we must compute the moles of gaseous fluorine (molar mass: 38 g/mol) as shown below:
Thus, we compute the volume with the proper ideal gas constant, R:
Best regards.
The formula used for determining gas pressure, volume and temperature interaction would be PV=nRT.
<span>• What is the temperature in Kelvins?
</span>You already right at this part. Kelvin temperature formula from celsius should be:
K= C+273.15=
<span>K= 27 +273.15 = 300.15
It is important to remember that the formula in this question is using Kelvin unit at temperature, not Celcius or Fahrenheit.
</span>
<span>• Assuming that everything else remains constant, what will happen to the pressure if the temperature decreases to -15 ºC?
</span>In this case, the temperature is decreased from 27C into -15C and you asked the change in the pressure.
Using PV=nRT formula, you can derive that the temperature will be directly related to pressure. If the temperature decreased, the pressure will be decreased too.
<span> If you increase the number of moles to 6 moles, increase temperature to 400K and reduce the volume to 25 L, what will the new pressure be?
</span>PV=nRT
P= nRT/V
P= 6 moles* <span>0.0821 L*atm/(mol*K) * 400K/25L= 7.8816 atm</span>
Answer: -2.79°C
Explanation:
Supposing complete ionization:
Li2SO4 → 2 Li{+} + SO4{2-} [three ions]
(0.50 m Li2SO4) x 3 = 1.50 m ions
(1.50 m) x (1.86 °C/m) = 2.79°C change
0°C - 2.79°C = -2.79°C
Answer:
0.085 kg
Explanation:
1 g=0.001 kg OR 1 kg=1000 g
so 
=0.085 kg
