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artcher [175]
3 years ago
10

The Hubble constant, $H_{0}$, is the ratio of the recessional velocity of a galaxy to its distance. The Hubble constant is estim

ated to be 70 km/sec per million parsecs of distance. (One parsec is equal to 3.26 light years.) Based on this ratio, how many billions of light years away would a galaxy be if it had a recessional velocity of 300,000 km/sec?
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

14 billion light years away

Explanation:

v = Recessional velocity = 70km/s/million parsec

D = Proper distance

Hubble constant

70\ km/s=3260000\ ly\\\Rightarrow 1\ km/s=\dfrac{3260000}{70}\ ly

From Hubble's law we have the relation

v=H_0D\\\Rightarrow D=\dfrac{v}{H_0}\\\Rightarrow D=\dfrac{3260000}{70}\times 300000}\\\Rightarrow D=13971428571.42857\ ly

The distance in light years of the galaxy is 14 billion light years away

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True or False: Objects that have more mass also have more gravity.
Fantom [35]

Answer:

True

Explanation:

The smaller object usually moves towards the larger object, because the larger object has more mass than the smaller object, so it has a larger gravitational pull.

7 0
3 years ago
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If a hockey stick exerts a force of 40 N on a 0.5-kg puck, what will the
antoniya [11.8K]

Answer:

  B.  80 m/s²

Explanation:

F = ma

a = F/m = (40 N)/(0.5 kg) = 80 m/s²

3 0
3 years ago
How does kinetic energy connect or relate to Newtons second law of motion?
Orlov [11]
Newtons second law of motion: "T<span>he acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object."

kinetic energy is energy that an object posses while in motion and to get that it must have potential energy.</span>
8 0
2 years ago
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A child whose weight is 235 N slides down a 4.90 m playground slide that makes an angle of 37.0° with the horizontal. The coeffi
Basile [38]

Answer:

Explanation:

a) First, let's calculate the value of the Friction force, which is given by the formula:

Ff = u*W

As the Friction force has an X component, it would be:

Ff = u*m*g*cosФ

Where m*g is the weight of the child.

Solving for Ff:

Ff = 0.051 * 235cos37 = 9.57 N

Now, to get the energy transferred to thermal energy (or heat) we need to get the Work done, so:

Wf = Ff * d

Wf = 9.57 * 4.9 = 46.9 J

b) We need to get the downslope component of the child weight, which is:

Wy = 235sin37 = 141.43 N

As you can imagine, the gravity also does work, so:

Wg = Wy * d

Wg = 141.43 * 4.9 = 693 J

Now, let's get the kinetic energy, which can be obtained by this expression:

ΔKe = Wg - Wf

ΔKe = 693 - 46.9 = 646.1 J

The formula for kinetic energy is:

Ke = 1/2 m*V^2

We have the innitial speed which is 0.355 m/s, and the mass can be obtained by m*g so:

Fw= m*g ----> m = Fw/g

m = 235 / 9.8 = 23.97 kg

so the innitial energy is:

Ke = 1/2 * 23.97 * (0.355)^2

Ke = 1.51 J

This could be Ke1, so to get Ke2:

ΔKe = Ke2 - Ke1

Ke2 = Δke + Ke1

Ke2 = 646.1 + 1.51 = 647,61 J

Finally, the speed at the bottom would be:

v = √2Ke/m

v = √2*647.61/23.97

v = 7.35 m/s

7 0
3 years ago
A 15 N force and a 45 N force act on in object in opposite directions. What is the net force on the object?
vovikov84 [41]

Answer:

30N in the direction the 45N acts.

Explanation:

Fnet = F1 + F2 (the vector sum of the forces)

Assigning a positive direction to the 45N force and a negative direction to the 15N force gives:

Fnet = 45 - 15

Fnet = 30N

Since the answer is positive, it is in the direction the 45N force acts.

7 0
2 years ago
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