Molar mass of CaCl2 = 40+ ( 35.5 ×2)=110
Mr of Ca(OH)2 = 40+ (16+1)×2 =74
%of Ca = (40÷ 74)×10=...
1 m = 100cm...
1cm = (1÷100) m
So 45.5 cm = 45.5 ×(1÷100) =....
1km = 1000m
1m = 100 cm
1cm =10mm
So 1km = 1000×100×10 mm
Now convert
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
The species that is the conjugate acid is HC₂H₃O₂(aq). The correct option is d.
<h3>What are conjugate acid?</h3>
Conjugates acids are those acids which are made when an acid donates a proton to a base according to Bronsted Lowry theory.
In other words, we can say that it is an acid with hydrogen ion. An example is water (base) reacting with an acid to form the hydronium ion (conjugate acid).
Thus, the correct option is d, HC₂H₃O₂(aq).
Learn more about conjugate acid
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Answer
B I’m pretty sure
Explanation
