We can use the ideal gas equation to determine the temperature with the given conditions of mass of the gas, volume, and pressure. The equation is expressed
PV=nRT where n is the number of moles equal to mass / molar mass of gas. Substituting the given conditions with R = 0.0521 L atm/mol K we can find the temperature
Stereochemistry, a subdiscipline of chemistry, involves the study of the relative spatial arrangement of atoms that form the structure of molecules and their manipulation.
<h3>What is the use of stereochemistry?</h3>
Using stereochemistry, chemists can work out the relationships between different molecules that are made up from the same atoms. They can also study the effect on the physical or biological properties these relationships give molecules.
<h3>Why is it called stereochemistry?</h3>
The term “stereochemistry” is derived from the Greek “stereos” meaning solid—it refers to chemistry in three dimensions. Since nearly all organic molecules are three dimensional (with the exception of some olefins and aromatics to be discussed later), stereochemistry cannot be considered a branch of chemistry.
Learn more about stereochemistry here:
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brainly.com/question/13266152</h3><h3 /><h3>#SPJ4</h3>
<span>I'm assuming its cause the total mass is the same, changes between phases are physical... solid ice and liquid water have the same mass</span>
Answer: c. Salt and Water
Explanation:
For example;
When an Arrhenius acid such as; Tetraoxosulphate (VI) acid (H2SO4) reacts with an Arrhenius base such as Potassium hydroxide (KOH), the products formed in this neutralization reaction is a salt known as ''Potassium Sulphate'' (K2SO4) and ''Water'' (H2O).
H2SO4 + KOH -------------> K2SO4 + H2O
Answer:
11.6 grams of MgO can be produced with 4.63 grams of oxygen.
Explanation:
Mass of oxygen gas = 4.63 g
Moles of oxygen gas = 
According to reaction, 1 mole of oxygen gas gives 2 moles of magnesium oxide, then 0.1447 moles of oxygen gas will giv e:
of magnesium oxide
Mass of 0.2894 moles of magnesium oxide:
= 0.29 mol × 40 g/mol = 11.6 g
11.6 grams of MgO can be produced with 4.63 grams of oxygen.
