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Vsevolod [243]
3 years ago
15

A rock is dropped from a helght of 2.5 meters. What is its velocity when it reaches the ground?

Physics
1 answer:
Nataly_w [17]3 years ago
7 0

u=0 m/s

h=2.5m

Using kinematic eq:

{v}^{2}  -  {u}^{2}  = 2gh \\  {v}^{2}  -  {0}^{2}  = 2gh \\ v =  \sqrt{2gh}  \\ v =  \sqrt{2 \times 10 \times 2.5}  \\ v =  \sqrt{50}  \\ v = 7.07m/s

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The total displacement of the toy car at the given positions is 0.

The given parameters;

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  • <em>Second displacement of the car, = 8 cm right</em>
  • <em>Third displacement of the car, = 3 cm to the left</em>

The total displacement of the car is calculated as follows;

  • <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
  • <em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

\Delta x = - \ 5\ cm  \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

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If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you
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The friction force is 250 N

Explanation:

The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):

\sum F=ma

In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:

\sum F = 0 (1)

We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:

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